Answer:
11·699
Explanation:
Given the concentration of hydroxide ion in the solution is 5 × 
M
Assuming the temperature at which it is asked to find the pH of the solution be 298 K
<h3>At 298 K the dissociation constant of water is
</h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>
∴ pOH of the given solution = - log(5 × = -0·699 + 3 = 2·301
pH of the given solution = 14 - 2·301 = 11·699
∴ pH of the solution = 11·699
Answer:
In the chemical industry, lithium-based batteries are working most efficiently and replacing nickel-cadmium batteries. To study a redox reaction in a lithium battery let's take the example of Lithium Cobalt Oxide(LiCoO2).
Following is the overall reaction taking place in Lithium Cobalt Oxide battery. Reduction and oxidation takes place at Cathode and Anode respectively. that is why it is called a redox reaction.
Reaction at cathode:
Cathode: CoO2+Li+e−→ LiCoO2 (Reduction)
Reaction at Anode:
Anode: LiC6→ C6+Li++e− (Oxidation)
Overall reaction:
LiC6 + CoO2→ C6 + LiCoO2
beacuse bromine is more reactive than iodine.
True
this needs to be 20 characters sorry i had to right this
