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Brilliant_brown [7]
3 years ago
8

What is the difference between ionic and covalent bonds?

Chemistry
1 answer:
Svetllana [295]3 years ago
5 0
Ionic bonds result when electrons are tranfered between atoms. Covalent bonds result when valence electrons are shared between atoms. You should be able to identify whether an ionic or covalent bond is being formed between atoms.
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The first ionization energy of na(g) is 0.50 mj/mole. can a photon with a wavelength of 500 nm ionize a sodium atom? explain.
Sonbull [250]
<h3>Answer:</h3>

              No, a photon with a wavelength of 500 nm can't  ionize a sodium atom.

<h3>Explanation:</h3>

Step 1: Find out Energy of given wavelength:

The relation between wavelength and frequency is as follow,

                                                        υ = c / λ

where

           υ = frequency = ?

           c = velocity of light = 3.0 × 10⁸ ms⁻¹

           λ = wavenumber = 500 nm = 500 × 10⁻⁹ m

Putting the given values,

                                 υ = 3.0 × 10⁸ ms⁻¹ / 500 × 10⁻⁹ m

                                 υ = 6.0 × 10¹⁴ s⁻¹

Also we know that,

                                                        E = h υ

Where;

           E  =  Energy

           h  =  Plank's Constant  =  6.6262 × 10⁻³⁴ Js

Putting value of frequency,

                                 E = 6.6262 × 10⁻³⁴ Js × 6.0 × 10¹⁴ s⁻¹

                                 E = 3.97 × 10⁻¹⁹ J

Step 2: Compare given energy and calculated energy:

As we know,

                                          0.5 mJ  =  500000 J

Also,

                                     500000 J  >  3.97 × 10⁻¹⁹ J

<h3>Conclusion:</h3>

                           The energy of calculated wavelength of photon is less than 0.5 mJ hence, it is unable to ionize sodium atom.

4 0
3 years ago
Read 2 more answers
Calculate the work done when a force of 4 N pulls a box along the floor for a distance of 0.3 m.
Yuki888 [10]

Answer:

<h2><em>1</em><em>.</em><em>2</em><em> </em><em>Joule</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>Force=</em><em>4</em><em> </em><em>N</em>

<em>Distance</em><em>=</em><em>0</em><em>.</em><em>3</em><em> </em><em>m</em>

<em>Now</em><em>,</em>

<em>work = f \times d \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 4 \times 0.3 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 1.2 \: joule</em>

<em>hope</em><em> </em><em>this </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
4 years ago
Convert 100.6 degrees F to<br> degrees C.
Llana [10]

Answer: 38.111111

Explanation: (100.6°F − 32) × 5/9 = 38.111°C

8 0
4 years ago
A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does
VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 200 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.16\times 1000}{200}=0.81M

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol

Mass of solution = Density\times Volume=1.05g/ml\times 200ml=210g

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg

Therefore, the molality of solution is 0.82m

3 0
3 years ago
A 5.20 mol sample of solid A was placed in a sealed 1.00 L container and allowed to decompose into gaseous B and C. The concentr
ELEN [110]

Answer:

2.60 moles of A remaining.

Explanation:

According to  Le Chatelier's principle, the equilibrium would shift if the volume, concentration, pressure, or temperature changes.

In this question, we were told that  the volume doubles, that implies that we would have to double the molarity of B/ C (since B=C.)

However, it is obvious and clear from the given equation of the reaction that  A is  solid in it's activity = 1. Hence, it is then ignored.

So doubling B would be 1.30 M × 2 = 2.60 M

i.e 2.60 M moles of A was consumed.

Now;  the number of moles of A remaining  is 5.20 - 2.60 = 2.60 moles of A remaining.

5 0
3 years ago
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