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Drupady [299]
2 years ago
8

Which elements do not usually interact with other elements?

Physics
2 answers:
d1i1m1o1n [39]2 years ago
7 0
Noble gasses ( insert gases)
kobusy [5.1K]2 years ago
6 0

Noble gases are the elements which do not usually interact with other elements.

Explanation:

The elements present in the last column of the periodic table defined as noble gases are the elements which do not interact with other elements.

The elements present in the noble gas series have fully occupied valence orbital and thus they are highly stable and does not undergo any kind of chemical reaction with other elements.

They are also termed as inert gases.

They are mostly used as ionizing gases as they can ionize the other gases easily.

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Which value would complete the last cell?
GREYUIT [131]

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

5 0
3 years ago
A current of 6.0 A runs through a circuit for 2.5 minutes.
Mekhanik [1.2K]
Current is measured as charge per unit time. To get change, simply multiply the current with time:

6A*2.5mins = 6A*(2.5*60)seconds = 900Coulombs
5 0
3 years ago
Read 2 more answers
How many elections do atoms typically “want” in their valence shell? This is timed, please help!
9966 [12]

Answer:

They typically "want" 2, so the answer is C.

Explanation:

4 0
3 years ago
2 * 1.5 * (.850/2)^2A small ball with mass 1.50 kg is mounted on one end of a rod 0.850 m long and of negligible mass. The syste
grin007 [14]

Answer

given,

mass of the rod = 1.50 Kg

length of rod = 0.85 m

rotational velocity = 5060 rev/min

now calculating the rotational inertia of the system.

I = m L^2        

where L is the length of road, we will take whole length of rod because mass is at  the end of it.      

I = 1.5 \times 0.85^2  

I = 1.084 kg.m²                        

hence, the rotational inertia the system is equal to I = 1.084 kg.m²

8 0
2 years ago
4.5 billion km, the average separation between the sun and Neptune (report answer in hours). How long does it take light to trav
Liula [17]

Answer:

t = 4.17 hours

Explanation:

given,

The distance between Sun and Neptune, d = 4.5 billion Km

                                                                         = 4.5 x 10⁹ Km

                                                                          = 4.5 x 10¹¹ m

The velocity of light, c = 3 x 10⁸ m/s

The velocity is always equal to displacement by the time.

                                           <em>V = d / t    m/s</em>

∴                                           t = d / V

                                               = 4.5 x 10¹¹ m / 3 x 10⁸ m/s

                                               = 15,000 s

                                               = 4.17 h

Hence, the time taken by the light rays to reach the Neptune is, t = 4.17 h

4 0
2 years ago
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