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3 years ago

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What evidence can you cite for the particle nature of light? 1. Refraction phenomenon of light 2. The many colors of light 3. Di

ffraction phenomenon of light

1 answer:

GalinKa [24]3 years ago

3 0

Evidence for the particle nature of light are not: 1. refraction, 2. many colors of light, 3. diffraction. These are all phenomenon that support wave theory of light. Evidence for particle nature of light is photoelectric effect. Because it was discovered that you need discrete energies of light to eject electrons from a metal surface and not continuous as the wave theory of light suggests.

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Why does water in hot springs always remain hot? Why doesn't it's thermal energy spread out?

Alex_Xolod [135]

Answer:

Explanation:

because of the tempature

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Which of the following statements is

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Read 2 more answers

When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical

Sergio039 [100]

Explanation:

As per the problem,

$\Delta U = (V_{B} - V_{A})(-q) > 0$

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or, $V_{A} > V_{B}$

Therefore, both positive and negative charge will move from $V_{A}$ to $V_{B}$ and as $V_{B} < V_{A}$ so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

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3 years ago

. A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is orient

Dmitriy789 [7]

Answer:

The magnetic flux through surface is $2.22 \times 10^{-3}$ Wb

Explanation:

Given :

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Radius of circle $r = 0.10$ m

Angle between field and surface normal $\theta =$ 25°

From the formula of flux,

$\phi = B.A$

$\phi = BA\cos \theta$

Where $\theta =$ angle between magnetic field line and surface normal, $A =$ area of circular surface.

$A = \pi r^{2}$

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$A = 0.0314$ $m^{2}$

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4 years ago

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ivolga24 [154]

The De Broglie's wavelength of a particle is given by:

$\lambda=\frac{h}{p}$

where

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p is the momentum of the particle

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and if we substitute this into the previous equation, we find the De Broglie wavelength of the electron:

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So, the answer is True.

7 0

3 years ago