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Serhud [2]
3 years ago
14

Convert : a) 110°C into °F b) 32°F into °C Please show your work if possible .​

Physics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

110°C = 230°F

32°F = 0°C

Explanation:

(110*9/5)+32=230

(32-32)*5/9=0

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A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the bod
Leviafan [203]

Answer:

36 J

Explanation:

Let's start off with the Kinetic Energy formula: 1/2mv^{2}

So to find the <em>change</em> in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.

*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the <em>mass</em>, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.

If 6 kg is the MASS:

Beginning: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2 = \frac{1}{2}(6)(2 squared)= \frac{1}{2}(6)(4)= 12 J

End: find the kinetic energy.

Plug in all parts of the formula: 1/2mv^2=\frac{1}{2}(6)(4 squared)=\frac{1}{2}(6)(16)= 48 J

Answer:

36 J

If 6 kg is the WEIGHT:

We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:

Weight = mass x acceleration due to gravity

6 = mass x 9.8

6 = 9.8m

*Divide both sides*

mass = 0.6 kg

Now, we can use the mass to find the kinetic energy.

Beginning: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2 = \frac{1}{2}(0.6)(2 squared)= \frac{1}{2}(0.6)(4)= 1.2 J

End: find the Kinetic Energy

Plug in all parts of the formula: 1/2mv^2=\frac{1}{2}(0.6)(4 squared)=\frac{1}{2}(0.6)(16)= 4.8 J

Answer:

3.6 J

(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)

4 0
3 years ago
A mass of 0.54 kg attached to a vertical spring stretches the spring 36 cm from its original equilibrium position. The accelerat
UNO [17]
<h2>Spring constant is 14.72 N/m</h2>

Explanation:

We have for a spring

            Force =  Spring constant x Elongation

            F = kx

Here force is weight of mass

           F = W = mg = 0.54 x 9.81 = 5.3 N

Elongation, x  = 36 cm = 0.36 m

Substituting

           F = kx

           5.3 = k x 0.36

             k = 14.72 N/m

Spring constant is 14.72 N/m

6 0
3 years ago
Find the frequency of the second overtones of a pipe 45 cm long if the pipe is closed at one end
Novosadov [1.4K]
C. Hoped this helped
6 0
3 years ago
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56. What is the range of magnitudes that can be attained from the
Svetach [21]

Answer:

Explanation:

Given the magnitude of the forces, 7N and 2N, the minimum combining force acting on the forces are when the force's is acting in opposite direction.

Magnitude of the force in opposite direction is 7N - 5N = 2N

The maximum combining force occurs when they act in the same direction. Magnitude of the force in the same direction is 5N+7N = 12N

Hence the range of magnitude requires is 2N≤F≤12N

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kumpel [21]
Opposite from the angle is 134.7905

Adjacent to the angle is 192.5007
6 0
4 years ago
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