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3 years ago

Use Euler’s Formula to find the missing number. Faces: 8 Edges: _____ Vertices: 6

Mathematics

1 answer:

taurus [48]3 years ago

7 0

Answer:

The number of edges is $E=12$

Step-by-step explanation:

we know that

The Euler's formula state that, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

$V- E + F = 2$

In this problem we have

$F=8, V=6$

substitute and solve for E

$6- E + 8 = 2$

$E=6 + 8 -2=12$

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ALGEBRA QUESTION WILL GIVE BRAINLIEST IF CORRECT!!!

Ulleksa [173]

Answer:

Step-by-step explanation:

(f + g)(x) simply means that you are adding together the 2 functions that are written in terms of x.

$x^3-x+x^3+2x^2-10$

The only like terms we have there are the x-cubed's, so

$2x^3+2x^2-x-10=(f+g)(x)$

3 0

3 years ago

Please solve in the picture!

iris [78.8K]

Answer:

Step-by-step explanation:

As we know that from a theorem,

A greater angle of a triangle is opposite a greater side. Let ABC be a triangle in which angle ABC is greater than angle BCA; then side AC is also greater than side AB. For if it is not greater, then AC is either equal to AB or less.

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6 0

3 years ago

Read 2 more answers

Have Retirement Benefits

charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

Step-by-step explanation:

The information provided is:

Yes No Total

Men 275 50 325

Women 150 25 175

Total 425 75 500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

$P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55$

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

$P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10$

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

$P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45$

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0

3 years ago

What fraction is equivalent to eight tentHs

aleksklad [387]

8/10 is equivalent to 4/5. just divide both 8 and 10 by 2

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago