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slavikrds [6]
3 years ago
13

Balance the equation: Ba(OH)2(aq) + H3PO4(aq)

Chemistry
1 answer:
alexgriva [62]3 years ago
5 0

The products of the unbalanced reaction are as follows:

Ba(OH)₂ (aq) + H₃PO₄(aq) → Ba₃(PO₄)₂(s) + H₂O(l)

This is an acid base reaction where Ba(OH)₂ is the base and H₃PO₄ is the acid. Acid base reaction is also known as neutralization reaction where the acid and base react with each other to form salt and water. In this reaction Ba₃(PO₄)₂ is the salt. Also barium phosphate (Ba₃(PO₄)₂) is insoluble in water and forms a solid precipitate.

The balanced reaction is as follows:

3Ba(OH)₂ (aq) + 2H₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6H₂O(l)

There are three Ba from Ba₃(PO₄)₂ on the product side of the equation, so to balance 3 coefficient was placed before Ba(OH)₂. Similarly, 2 coefficient was placed before H₃PO₄ on the reactant side to balance the two phosphate from Ba₃(PO₄)₂ on the product side. Finally, 6 coefficient was placed before H₂O on the product side, to balance the number of H and O atoms on both side of the equation.



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Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction: C(s)+2H2O(g)→2H2
madam [21]

The question is incomplete , complete question is:

Hydrogen, a potential future fuel, can be produced from carbon (from coal) and steam by the following reaction:

C(s)+ 2 H_2O(g)\rightarrow 2H_2(g)+CO_2(g).\Delta H=?

Note that the average bond energy for the breaking of a bond in CO2 is 799 kJ/mol. Use average bond energies to calculate ΔH of reaction for this reaction.

Answer:

The ΔH of the reaction is -626 kJ/mol.

Explanation:

C(s)+ 2 H_2O(g)\rightarrow 2H_2(g)+CO_2(g).\Delta H=?

We are given with:

\Delta H_{H-O}=459 kJ/mol

\Delta H_{H-H}=432 kJ/mol

\Delta H_{C=O}=799 kJ/mol

ΔH =  (Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

\Delta H=(4\times \Delta H_{O-H})-(2\times \Delta H_{H-H}+2\times\Delta H_{C=O})

=(4\times 459 kJ/mol)-(2\times 432 kJ/mol+2\times 799 kJ/mol

\Delta H=-626 kJ/mol

The ΔH of the reaction is -626 kJ/mol.

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Answer:

the second answer

Explanation:

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