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slavikrds [6]
3 years ago
13

Balance the equation: Ba(OH)2(aq) + H3PO4(aq)

Chemistry
1 answer:
alexgriva [62]3 years ago
5 0

The products of the unbalanced reaction are as follows:

Ba(OH)₂ (aq) + H₃PO₄(aq) → Ba₃(PO₄)₂(s) + H₂O(l)

This is an acid base reaction where Ba(OH)₂ is the base and H₃PO₄ is the acid. Acid base reaction is also known as neutralization reaction where the acid and base react with each other to form salt and water. In this reaction Ba₃(PO₄)₂ is the salt. Also barium phosphate (Ba₃(PO₄)₂) is insoluble in water and forms a solid precipitate.

The balanced reaction is as follows:

3Ba(OH)₂ (aq) + 2H₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6H₂O(l)

There are three Ba from Ba₃(PO₄)₂ on the product side of the equation, so to balance 3 coefficient was placed before Ba(OH)₂. Similarly, 2 coefficient was placed before H₃PO₄ on the reactant side to balance the two phosphate from Ba₃(PO₄)₂ on the product side. Finally, 6 coefficient was placed before H₂O on the product side, to balance the number of H and O atoms on both side of the equation.



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Answer: The molar enthalpy of formation for paraffin wax  is  -2460.5 kJ

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C_{25}H_{52}(g)+38O_2(g)\rightarrow 25CO_2(g)+26H_2O(g)

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\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_{25}H_{52}}\times \Delta H_{C_{25}H_{52}})]

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