Answer:
moles of glucose
<u>2.3166 moles of glucose</u>
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Explanation:
The balance reaction for the formation of glucose is :
here , CO2 = carbon dioxide
H2O = water
C6H12O6 = glucose
O2 = Oxygen
According to this equation :
6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2
We are asked to calculate the mole of Glucose from carbon dioxide.
So,
6 mole of CO2 produce = 1 mole of C6H12O6
1 mole of CO2 will produce =
moles of glucose
13.9 moles of CO2 will produce :
=2.3166 moles of glucose
Note : first , Always calculate for one mole (By dividing)
. After this , multiply the answer with the moles given.
Always write the substance whose amount is asked(glucose) to the right hand side
Hey there!
Great question;)
Answer:It is neutrally charged, because it has the same number of electrons(negatively charged ions) and protons(positively charged ions)
I hope this helps;)
Answer:
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
Explanation:
The equation used to calculate the constant for first order kinetics:
.....(1)
Rate law expression for first order kinetics is given by the equation:
![t=\frac{2.303}{k}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
......(2)
where,
k = rate constant
=Half life of the reaction = 
t = time taken for decay process = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the reactant = 0.163 M
[A] = amount left after time t = 66.8% of
[A]=
t = 1,409.19 s
1 minute = 60 sec
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
It could be
C + 2Cl2 ➡️ CCl4
I decided this because I believe this is the only way you could make this a balanced equation. To be a balanced equation Both sides of the equation has the same number of atoms for each element. Carbon has 1 atom and chlorine has 4.
