Na = 6.02·10²³ 1/mol; Avogadro constant (the number of constituent particles, in this example atoms, that are contained in the amount of substance given by one mole).

N(C) = n(C) · Na.

N(C) = 2 mol · 6.02·10²³ 1/mol.

N(C) = 12.04·10²³ = 1.204·10²⁴; number of carbon atoms in a sample.

5 0

4 years ago

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What is a paper clip, a colloid? solution? or a suspension?

Galina-37 [17]

Explanation:

a colloid is a nonuniform mixture of a solute and a solvent in which the particles are permanently suspended.

solution is a uniform mixture of a solute and a solvent.

suspension is a nonuniform mixture of a solute and a solvent in which the particles are temporary suspended

paper clip is used to hold papers in position

6 0

3 years ago

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(b) Describe how Aluminium chloride can be separated from a mixture of aluminium chloride

Elodia [21]

Answer:

Since AlCl3 sublimes and NaCl does not sublime sublimation process will separate the two. Heat the mixture, aluminium chloride sublimes into vapour and forms the sublimate on the cooler parts of heating tube sodium chloride will remain at the bottom of the heating tube.

Explanation:

I hope it helps you ..

8 0

3 years ago

The volume of a sample of hydrogen is 771.8 mL and it exerts 638.7 mm Hg pressure at 6.5 ºC. What volume does it occupy at stand

slamgirl [31]

Answer:

627mL (May be something is wrong with the choices)

Explanation:

First step: Ideal gas Law to get the moles

P . V = n . R . T

where P is pressure in atm (638.7 mmHg)

V is volume in L

n, the number of moles, the unknow value at this time

R the Ideal gas constant 0.082 L.atm/mol.K

T, the temperature in K (°C + 273)

760 mmHg ___ 1 atm

638.7 mmHg ___ (638.7 /760) = 0.84 atm

771,8 mL / 1000 = 0.7718 L

6.5°C + 273 = 279.5 K

0.7718 L . 0.84atm = n. 0.082 L.atm/mol.K . 279.5K

0.7718 L . 0.84atm /0.082 mol.K/L.atm . 279.5K = n

0,028 moles = n

Standard temperature and pressure are 273K and 1 atm

1 atm . Volume = 0,028 moles . 0.082 L.atm/mol.K . 273K

Volume = (0,028 moles . 0.082 L.atm/mol.K . 273K) /1atm

Volume = 0,6268 L = 627mL

5 0

3 years ago