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nadya68 [22]
3 years ago
10

Two runners start a race. After 2 seconds, they both have the same velocity. If they both started at the same time, how do their

average accelerations compare?
Physics
2 answers:
djyliett [7]3 years ago
7 0

let each runner starts from rest

v₀ = initial velocity of each runner = 0 m/s

t = time of travel = 2 sec =

a = average acceleration

average acceleration is given as

a = (v - v₀)/t

inserting the values

a =  (v - 0)/t

a = v/t

since each runner gains equal amount of speed in given time interval of "t". hence the average acceleration of each runner is same.

arsen [322]3 years ago
3 0

Answer:

Two runners start a race. After 2 seconds, they both have the same velocity.  they both started at the same time, how do their average velocities compare? They have the same acceleration rate.

Explanation:

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An Oven

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A 0.02kg dart is loaded into a toy spring gun by compressing the spring 6cm. If the spring has a constant of 20 N/m, find… a. Th
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a) 0.036 J b) 0.036J c) 0.036 d) 1.9m/s e) 0.18 m

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Mass of the dart = 0.02kg, the spring was compressed to 6cm

Work needed to compress the spring = 1/2*k*x ^2 where k is the force constant of the spring in N/m, x is the distance it was compressed in m

Work needed to compress the spring = 0.5 * 20* 0.06^2 since 6cm = 6 / 100 = 0.06 m

Work needed to compress the spring = 0.036J

b) the total energy stored in the spring = the work done to compress the spring = 0.036J

c) kinetic energy of the dart as it leaves the the spring = elastic potential energy stored in the spring = the work done in compressing the = 0.036J using the law of conservation of energy; energy is neither created nor destroyed but transformed from one form to another.

d) 1/2mv^2 = 0.036

mv^2 = 0.036*2

v^2 = 0.036*2 / 0.02 = 3.6

v = √3.6 = 1.897 approx 1.9m/s

e) kinetic energy of the dart = work done against gravity to get the body to height h

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A 3.0kg weight W is initially at rest on incline AB, which is raised 40° above the horizontal. The effective coefficient is
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(a) The acceleration of the system is determined as 1.58 m/s².

(b) The relative weight of P is pounds is determined as 0.14 lb.

<h3>Acceleration of the system</h3>

The acceleration of the system is calculated as follows;

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T = m₁a ----(2)

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5.67 = 3.6a

a = 5.67/3.6

a = 1.58 m/s²

<h3> Relative Weight of P</h3>

W = ma

W = 0.4 x 1.58

W = 0.632 N = 0.14 lb

Learn more about weight here: brainly.com/question/2337612

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