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pav-90 [236]
3 years ago
10

Pyrite is called "fool's gold" because it looks a lot like gold. Which properties can be used to tell gold and pyrite apart?

Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

The answer is steak

Explanation:

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mel-nik [20]
The density of salt water is 1.025 kg/liters .
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3 years ago
If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at a constant temperature. What is the new volume​
wel

Answer :

=748

⋅22.5

725

=23.2L

3 0
4 years ago
Solve the enthalpy of formation NH3(g) -46.11
lora16 [44]
I think 43.12 I’m not that good with math
3 0
4 years ago
The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0
4 years ago
55 kg of liquefied natural gas (lng) are stored in a rigid, sealed 0.17 m3 vessel. in this problem, model lng as 100% methane. d
dexar [7]

I am assuming that the problem ask for the pressure in the system. To be able to calculate this, we first assume that the system acts like an ideal gas, then we can use the ideal gas equation to find for pressure P.

P V = n R T

where,

P = Pressure (unknown)

V = 0.17 m^3

n = moles of lng / methane

R = gas constant = 8.314 Pa m^3 / mol K

T = 200 K

We find for the moles of lng. Molar mass of methane = 16 kg / kmol

n = 55 kg / 16 kg / kmol

n = 3.44 kmol CH4 = 3440 mol

 

Substituting all the values to the ideal gas equation:

P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3

P = 33,647,247 Pa

<span>P = 33.6 MPa</span>

6 0
3 years ago
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