Answer:
1.5 m
Explanation:
Length. L = 12 m
Width, W = 16 m
Area, A = 12 x 16 = 192 m^2
Let the width of pavement be d.
The new length, L' = 12 + 2d
the new width, W' = 16 + 2d
New Area, A' = L' x W' = (12 + 2d)(16 + 2d) = 192 + 56 d + 4d^2
Difference in area = A' - A
285 = 192 + 56 d + 4d^2 - 192
93 = 56 d + 4d^2
4d^2 + 56 d - 93 = 0
\
d = 1.5 m
Thus, the width of the pavement is 1.5 m.
Answer:
a) 400.4Joules
b) 262.69Joules
Explanation:
Work is said to be done if the force applied to an object cause the object to move through a distance
Workdone = Force × Distance
Given
Force = 76N
Distance= 5.2m
Work done = 77 × 5.2
Work done = 400.4Joules
b) If the force is exerted at an angle of 41°
Work done = Fdsin theta
Work done = 77(5.2)sin41
Work done = 400.4sin41
Work done = 262.69Joules
the machine shown in the diagram is called a tramp.
the height of the tramp is 5 and the length is 12
Answer:
4.13Hz
Explanation:
f1 = 1/t1 = 1/0.022 = 45.45 Hz
f2 = 1/t2 = 1/0.0242= 41.32 Hz
No. of beats
= 45.45- 41.32
~ 4.13Hz
