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Yanka [14]
3 years ago
8

Maria poured 25 grams of water into a beaker. She stirred in 5 grams of salt. The salt dissolved. What is the total mass of Mari

a’s solution of salt water?
Chemistry
2 answers:
Ahat [919]3 years ago
7 0

Answer:

The answer to your question is: 30 g

Explanation:

Data

mass of water = 25 g

mass of salt = 5 g

Process

total mass = mass of water + mass of salt

                 = 25 + 5

                 = 30 g

vovangra [49]3 years ago
4 0

Answer:30

Explanation:25+5=30

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You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

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\boxed{\text{36 mL}}

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\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

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\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

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c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

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