1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashutka [201]
3 years ago
12

2 word that describe cell in organism

Chemistry
1 answer:
castortr0y [4]3 years ago
3 0

complex and fundamental

You might be interested in
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
2 years ago
A blood test shows clumps only in wells containing anti-A and anti-B antibodies. The Rhesus test was negative. Which is the corr
enyata [817]
The correct blood type is AB-
3 0
3 years ago
What are the four categories commonly used to classify chemicals and chemical agents in the graphic communications industry
Oduvanchick [21]

Answer:

Organic

Plate making

Ink mists

Gas, fumes and dust

Explanation:

the four categories commonly used to classify chemicals and chemical agents in the graphic communications industry are Organic ,Plate making ,Ink mists, Gas, fumes and dust.

Organic refer to those chemicals gotten from living matter and are natural.

Plate making refers to how plates are make and it carry image in the printing process.

Ink mist gotten from ink is use in graphic designs for painting and color indication.

5 0
3 years ago
What is the mass number of an atom of chlorine that has 18 neutrons
larisa [96]
Hi, the answer is 34.45 , basically 34.
4 0
2 years ago
Read 2 more answers
If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the
igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if  concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3.

Evaluating \ln(64) / \ln(4) on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0
3 years ago
Other questions:
  • 1.15 g of a metallic element reacts with 300 cm3 of oxygen at 298 K and 1 atm pressure, to form. an oxide which contains O2– ion
    9·1 answer
  • Select the compounds that cannot undergo friedel crafts alkylation. check all that apply. check all that apply. aniline phenol k
    11·1 answer
  • HELP with these 2 questions asap
    14·2 answers
  • On the basis of electronegativity, which of these pairs of elements is most likely to form polyatomic ions?
    14·1 answer
  • Bond order of n2<br><br>bond order of N2 ​
    9·1 answer
  • What are the mountainous parts of the moon called? Question 3 options: craters terrae maria regolith
    12·2 answers
  • Write a causal question based on the information in the passage
    7·1 answer
  • Number the steps for balancing equations:
    15·2 answers
  • What is the H concentration in a solution with a pH of 1. 25? Round to the nearest hundredth. × 10n M n=.
    7·1 answer
  • 2. Calculate the atomic mass of the following elements i. Silicon ii. Magnesium iii. Potassium.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!