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Andrei [34K]
3 years ago
9

You will be using the observations given in the scenarios i - vi below to determine which of the following is true for G (a - c)

, which of the following is true for S (d - f) and which of the following is true for H (g - i).
Scenarios:

i. A spontaneous reaction is taking place in a flask. When you touch the flask, it feels cold and gets colder as the reaction progresses.
Input format: in alphabetical order something like c,d,i

ii. A spontaneous reaction is taking place in a flask as evidenced by the formation of gas bubbles. When you touch the flask, it feels hot and gets hotter as the reaction progresses.
Input format: in alphabetical order something like c,d,i

iii. A spontaneous reaction is taking place in a flask. When you touch the flask, it feels hot and gets hotter as the reaction progresses.
Input format: in alphabetical order something like c,d,i

iv. A spontaneous reaction is taking place in a flask. You notice the formation of gas bubbles intensifies as the reaction progresses.
Input format: in alphabetical order something like c,d,i

v. A solid in a closed flask begins to melt. (You can consider this a phase change.)
Input format: in alphabetical order something like c,d,i

vi. A liquid begins to appear on the inside of a closed flask. At first glance before the liquid began to appear, you might have thought the flask was empty. (You can consider this a phase change.)


a. The sign of G is positive.
b. The sign of G is negative.
c. Cannot determine the sign of G from the information given.
d. The sign of S is positive.
e. The sign of S is negative.
f. Cannot determine the sign of S from the information given.
g. The sign of H is positive.
h. The sign of H is negative.
i. Cannot determine the
Chemistry
1 answer:
WITCHER [35]3 years ago
5 0

Answer:

A spontaneous reaction is taking place in a flask. When you touch the flask, it feels cold and gets colder as the reaction progresses........(c,f,g)

A spontaneous reaction is taking place in a flask as evidenced by the formation of gas bubbles. When you touch the flask, it feels hot and gets hotter as the reaction progresses.... (c,d,h)

A spontaneous reaction is taking place in a flask. When you touch the flask, it feels hot and gets hotter as the reaction progresses....(c,f,h)

A spontaneous reaction is taking place in a flask. You notice the formation of gas bubbles intensifies as the reaction progresses....(c,d,I)

A solid in a closed flask begins to melt. (You can consider this a phase change.)....(b,d,g)

A liquid begins to appear on the inside of a closed flask. At first glance before the liquid began to appear, you might have thought the flask was empty. (You can consider this a phase change.)....(a,e,h)

Explanation:

Now it is necessary here to state the equation for ∆G

∆G= ∆H-T∆S

The values of ∆G depends on the relative values of ∆H, T and ∆S.

When heat is evolved by a system, ∆H is negative, when heat is absorbed by a system, ∆H is positive.

When gases are evolved, ∆S is positive, when gases turn to liquids or solids ∆S is negative.

Let us also recall that, for the melting process ∆S positive ( solid changes to liquid), ∆H is positive(energy is absorbed) and T increases( the substance is heated). Hence ∆G is negative

For the condensation process; ∆H is negative (heat is evolved), ∆S is negative (gas changes to liquid) and T is decreased hence ∆G is positive.

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what is the indication that tells us what charge a transitional metal has since they dont have a set trend
Arlecino [84]

Answer:

Roman numbering in IUPAC naming system

Explanation:

This is quite an open question. Let's firstly separate the periodic table into two standard groups: group A elements and group B elements (transition metals).

The charge (or the oxidation state) of an element in group A can be identified by the group number. For example, group 1A elements would always have a charge of +1, as they have only one valence electron to lose.

Similar trend applies to group 2A: each element in that group would have a charge of +2, as each atom has 2 valence electrons to lose to become a cation.

You will notice that this is true fro group 3A and group 4A as well. Now, since an octet is the desired state for any species, starting with group 5A, it's easier to gain 3 electrons for species than lose 5 electrons to obtain an octer, meaning we'd expect -3 oxidation state for group 5A elements, -2 oxidation state for group 6A elements and -1 oxidation state for group 7A elements.

Notice that in the majority of cases, this is the standard trend and we'd generally only have one predominant oxidation state.

Considering group B, the transition metals, most of them have several oxidation states. That's why we usually memorize the ones which only have one oxidation state (such as zinc, silver) and in any other case when a transition metal has several oxidation states, they're identified in the name by using Roman numbering system.

Let's look at an example. Assume the problem states we have a salt which is iron chloride. This would be an improper name, as iron has two oxidation states: +2 and +3. That's why we have the rules of IUPAC naming to avoid ambiguity. If we had iron with an oxidation state of +2, we'd call the salt iron(II) chloride. An oxidation state of +3 would indicate iron(III) chloride.

To summarize, the main key of knowing the charge of a transition metal in a compound is to follow the IUPAC naming rules.

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