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Oksana_A [137]
3 years ago
5

The temp of some water with a mass of 10.0 g and a specific heat of 4.2 changed from 25.0 ' C to 35.0 ' C. How much heat was abs

orbed?
A) 100 J
B) 230 J
C) 420 J
D) 600 J
Physics
2 answers:
Stella [2.4K]3 years ago
6 0
The correct answer is A
Marat540 [252]3 years ago
6 0

Actually, I just took this quiz and the answer is C) 420 J

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First,

\rho=\dfrac mV

where \rho is density, m is mass, and V is volume. We can compute the volume of the roll:

2.7\,\dfrac{\mathrm g}{\mathrm{cm}^3}=\dfrac{1275\,\mathrm g}V

\implies V\approx472.22\,\mathrm{cm}^3\approx4.72\,\mathrm m^3

When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness x. Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).

So we have

V=Ax

where A is the given area, so

4.72\,\mathrm m^3=\left(18.5\,\mathrm m^2\right)x

\implies x\approx0.255\,\mathrm m=255\,\mathrm{mm}

If we're taking significant digits into account, the volume we found would have been V=470\,\mathrm m^3, in turn making the thickness x=250\,\mathrm{mm}.

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