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yulyashka [42]
3 years ago
14

On a safari, a team of naturalists sets out toward a research station located 4.63 km away in a direction 38.7 ° north of east.

After traveling in a straight line for 2.13 km, they stop and discover that they have been traveling 25.9 ° north of east, because their guide misread his compass.
What are (a) the magnitude and (b) the direction (as a positive angle relative to due east) of the displacement vector now required to bring the team to the research station?
Physics
1 answer:
aleksandrvk [35]3 years ago
5 0

Exactly, it is a vector subtraction problem.  Let t=theta,

t1=38.7, d1=4.63;  t2=25.9, d2=2.13

v1=d1 <cos(t1), sin(t1)>=<3,6134, 2.8949>

v2=d2 <cos(t2), sin(t2)>=<1.9161, 0.9304>

Final vector

v3 = v1-v2

=<v3x, v3y>

=<1.6973, 1.9645>

where

v3x=d1*cos(t1)-d2*cos(t2)

v3y=d1*sin(t1)-d2*sin(t2)

The final vector v3 has therefore a magnitude of

||v3||=sqrt(1.6973^2+1.9645^2)=2.5962, and a direction of

theta=atan(1.9645/1.6973)=49.17 degrees  north of east

Note: all three vectors are in the direction of the first quadrant.

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Answer:

The magnitude of the resultant vector is 22.66 cm and it has a direction of 29.33°

Explanation:

To find the resultant vector, you first calculate x and y components of the two vectors M and N. The components of the vectors are calculated by using cos and sin function.

For M vector you obtain:

M=M_x\hat{i}+M_y\hat{j}\\\\M=15.0cm\ cos(20\°)\hat{i}+15.0cm\ sin(20\°)\hat{j}\\\\M=14.09cm\ \hat{i}+5.13\ \hat{j}

For N vector:

N=N_x\hat{i}+N_y\hat{j}\\\\N=8.0cm\ cos(40\°)\hat{i}+8.0cm\ sin(40\°)\hat{j}\\\\N=6.12cm\ \hat{i}+5.142\ \hat{j}

The resultant vector is the sum of the components of M and N:

F=(M_x+N_x)\hat{i}+(M_y+N_y)\hat{j}\\\\F=(14.09+6.12)cm\ \hat{i}+(5.13+5.142)cm\ \hat{j}\\\\F=20.21cm\ \hat{i}+10.27cm\ \hat{j}

The magnitude of the resultant vector is:

|F|=\sqrt{(20.21)^2+(10.27)^2}cm=22.66cm

And the direction of the vector is:

\theta=tan^{-1}(\frac{10.27}{20.21})=29.93\°

hence, the magnitude of the resultant vector is 22.66 cm and it has a direction of 29.33°

4 0
3 years ago
How are steam powered boats different from sailboats
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Explanation:

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I hope this helps!

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Two skaters, a man and a woman, are standing on ice. Neglect any friction between the skate blades and the ice. The mass of the
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Answer:

a₁ = 0.63 m/s²  (East)

a₂ = -1.18 m/s²  (West)

Explanation:

m₁ = 95 Kg

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a₁ = ?

a₂ = ?

To get the acceleration (magnitude and direction) of the man we apply

∑Fx = m*a   (⇒)

F = m₁*a₁         ⇒      60 N = 95 Kg*a₁    

⇒  a₁ = (60N / 95Kg) = 0.63 m/s²  (⇒)  East

To get the acceleration (magnitude and direction) of the woman we apply

∑Fx = m*a   (⇒)

F = -m₂*a₂         ⇒      60 N = -51 Kg*a₂    

⇒  a₂ = (60N / 51Kg) = -1.18 m/s²  (West)

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