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alexira [117]
4 years ago
14

What mass of f2 is needed to produce 120. g of pf3 if the reaction has a 78.1% yield?

Chemistry
1 answer:
lesya692 [45]4 years ago
6 0

write the equation for the reaction

that is 6 F2 +P4 =4 PF3

find the theoretical mass that is

let the theoretical yield be represented by y

theoretical yield = 78.1/100 = 120/y

y= 153.6 grams

find the number of moles of  PF3

moles = mass/molar mass

= 153.6/87.97 =1.746 moles

by use of mole ratio between  F2 :PF3 which is 6:4 the moles of F2 is therefore= 1.746 x 6/4 = 2.62 moles

mass = moles x molar mass

= 1.746 moles x38 g/mol = 99.6 grams

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For example, in the chemical reaction;

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faltersainse [42]

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Net ionic equation:

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Explanation:

Chemical equation:

K₂CO₃  +   CaCl₂    →   KCl  +  CaCO₃

Balance chemical equation:

K₂CO₃(aq)  +   CaCl₂(aq)    →   2KCl(aq)  +  CaCO₃(s)

Ionic equation:

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CO²⁻₃(aq)  +   Ca⁺²(aq)      →   CaCO₃(s)

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