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alexira [117]
3 years ago
14

What mass of f2 is needed to produce 120. g of pf3 if the reaction has a 78.1% yield?

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

write the equation for the reaction

that is 6 F2 +P4 =4 PF3

find the theoretical mass that is

let the theoretical yield be represented by y

theoretical yield = 78.1/100 = 120/y

y= 153.6 grams

find the number of moles of  PF3

moles = mass/molar mass

= 153.6/87.97 =1.746 moles

by use of mole ratio between  F2 :PF3 which is 6:4 the moles of F2 is therefore= 1.746 x 6/4 = 2.62 moles

mass = moles x molar mass

= 1.746 moles x38 g/mol = 99.6 grams

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There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
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