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Fudgin [204]
3 years ago
15

What is the maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3

?
Chemistry
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

6.79 g of phosphine can be produced

Explanation:

The reaction is this:

3H₂ + 2P → 2PH₃

We have the mass of the two reactants, so let's find out the limiting reactant, so we can work with the equation. Firstly, we convert the mass to moles (mass / molar mass)

6.2 g / 30.97 g/mol = 0.200 moles of P

4g / 2 g/mol = 2 moles of H₂

Ratio is 3:2.

3 moles of hydrogen react with 2 moles of P

Then, 2 moles of H₂ would react with (2 . 2)/ 3 = 1.3 moles of P.

We have only 0.2 moles of P, so clearly the phosphorous is the limiting reactant.

Ratio is 2:2. So 2 moles of P can produce 2 moles of phosphine. Therefore, 0.2 moles of P must produce the same amount of phosphine.

Let's convert the moles to mass ( mol . molar mass)

0.2 mol . 33.97 g/mol = 6.79 g

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<h3>What is the mole concept?</h3>
  • The Mole concept is used to express the amount of substance conveniently.
  • A mole is defined as the amount of substance that contains exactly 6.022 x 10²³ elementary particles of the given substance. Here, elementary particles refer to atoms, molecules, or ions.
  • This fixed number  6.022 x 10²³ is known as Avogadro Number and is denoted by N_A
<h3>How to calculate the number of moles?</h3>

The number of moles is given by

n=\frac{m}{M}

When given mass = molar mass of a substance, then no of moles is equal to 1 which is equivalent to 6.022 x 10²³.

We also know,

1 mole has 6.022 x 10²³ molecules of CH₃OH

According to the mole concept,

6.022 x 10²³ molecules of CH₃OH is equal to 1 mole

2.5 x 10²¹molecules of CH₃OH is equal to \frac{2.5\times10^2^1}{6.022 \times 10^2^3} moles

Thus, 2.5 x 10²¹molecules of CH₃OH are equal to 4.15 x 10⁻³ moles or 0.00415 moles

Learn more about the mole concept:

brainly.com/question/1427235

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