153g/mols I think this is the answer but not 100% sure.
Answer:
3.47 mol MnSO4
Explanation:
54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4
542.32g / 151.01g/mol = 3.47 mol MnSO4
Answer:
if it cannot be made to fit the new findings
<span>Silver oxalate dissociation equation is following:
</span><span>
Ag</span>₂C₂O₄(s) ⇄ 2Ag⁺(aq) + C₂O₄²⁻(aq)
According to reaction follows next stoichiometric ratio:
[Ag⁺] : [C₂O₄²⁻] = 2 : 1
[C₂O₄²⁻] = [Ag⁺] / 2
[C₂O₄²⁻] = (1.7×10⁻⁴)/2 = 8.5×10⁻⁵ M
So, solubility product constants for silver oxalate is:
Ksp = [Ag⁺]² x [C₂O₄²⁻]
Ksp = [1.7×10⁻⁴]² x [8.5×10⁻⁵]
Ksp = 2.46×10⁻¹²
