Which plant characteristic is the least important with regard to attracting bats? (1 point)

Chemistry

1 answer:

Sav [38]3 years ago

7 0

Answer:

O flower shape

Explanation:

Bats are just as important for pollination as insects and just like insects, plants use artifices to attract bats to their flowers, allowing them to have access to the pollen that will be taken elsewhere.

Bats are mainly attracted by the color and smell of flowers, the size and shape also play a role in attracting these animals, but the shape is less influential.

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write the equilibrium expression for the base ionization of the weak base of methylamine, ch3 nh2 . hint: first write the balanc

svetlana [45]

CH3NH2 + HOH ==> CH3NH3^+ + OH^-Which molecule/ion accepts a proton. That is the base. Which molecule/ion donates a proton. That is the acid.

A stable subatomic particle known by the symbol for "proton"

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Each atom. has a nucleus. that contains one or more protons. In order to keep the atomic electrons bound, they offer the central attractive electrostatic force. An element's defining characteristic, known as the atomic number, is the number of protons in the nucleus (represented by the symbol Z)

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4 0

1 year ago

Five million gallons per day (MGD) of wastewater, with a concentration of 10.0 mg/L of a conservative pollutant, is released int

hjlf

Answer:

a) The concentration in ppm (mg/L) is 5.3 downstream the release point.

b) Per day pass 137.6 pounds of pollutant.

Explanation:

The first step is to convert Million Gallons per Day (MGD) to Liters per day (L/d). In that sense, it is possible to calculate with data given previously in the problem.

Million Gallons per day $1 MGD = 3785411.8 litre/day = 3785411.8 L/d$

$F_1 = 5 MGD (\frac{3785411.8 L/d}{1MGD} ) = 18927059 L/d\\F_2 =10 MGD (\frac{3785411.8 L/d}{1MGD} )= 37854118 L/d$

We have one flow of wastewater released into a stream.

First flow is F1 =5 MGD with a concentration of C1 =10.0 mg/L.

Second flow is F2 =10 MGD with a concentration of C2 =3.0 mg/L.

After both of them are mixed, the final concentration will be between 3.0 and 10.0 mg/L. To calculate the final concentration, we can calculate the mass of pollutant in total, adding first and Second flow pollutant, and dividing in total flow. Total flow is the sum of first and second flow. It is shown in the following expression:

$C_f = \frac{F1*C1 +F2*C2}{F1 +F2}$