Answer:
a) 0.0130 m
b') w' = =6.46*10^{-3] m
Explanation:
given data:
\lambda of light = 633 nm
width of siit a =0.360 mm
distance from screen = 3.75 m
a) the first minima is located at
=
with of central fringe = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m
b)
width of the first bright fringe on either side of the central one = 
calculation for y_2
= 
w' = =6.46*10^{-3] m
I think it is a, b, and e. Hope it helps! :)
Work = (force) x (distance)
Work = (22 N) x (16 m)
<em>Work = 352 Joules</em>
True. Being an electrical engineer, you learn very quickly that current will take All paths of resistance. But, the higher the resistance the lower the voltage. So, if a high resistance is shorted and the current flows through the short, there will be some small voltage across it, so some small amount of current will still flow through the high resistance.
Answer:
The angular separation equals 
Explanation:
We have according to Snell's law
Using this equation for both the colors separately we have
Similarly for violet light we have
Thus the angular separation becomes
