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vaieri [72.5K]
3 years ago
6

If a switch is open in a series circuit with a battery trying to light a bulb, what will happen? The bulb will light up. O The s

witch is not working. O The bulb will not light up. HELP PLEASE THIS TEST IS IMPORTANT TO ME ​
Physics
2 answers:
stepan [7]3 years ago
8 0

Answer:

The bulb will not light up.

Explanation:

I just took the quiz.

almond37 [142]3 years ago
3 0

Answer:

The bulb will not light up

  • If the switch is open then the connection between the circuit broken and the bulb stops glowing

  • The circuit needs to be closed and connected.

  • The circuit is the closed path through which current flows.

  • It consists of cell , battery , wires, resistors etc

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A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the
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Used an app called Mephyso to do the calculation.

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3 years ago
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A top-fuel dragster accelerates from rest to a velocity of 100 m/s in 8 s. What is the acceleration?
seropon [69]

Answer:

100 m/s ÷ 8 = 12.5 m/s

Explanation:

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3 years ago
Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False
kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

\vec{L} = I \vec{\omega}

where I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2 is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2} so \vec{\omega} \neq 0 unless \vec{r} ║  \vec{v}.

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

7 0
3 years ago
What is the formula of the compound between calcium and sulfur that has the percent composition 55.6?
Yanka [14]

CaS is the empirical formula of the compound between calcium and sulphur that has the percent composition 55.6.

When percentages are given, we take a total mass of 100 grams.

Therefore the mass of each element is equal to the percentage given.

Mass of Ca = 55.6 g (given) of

S Mass = 44.4 g (100 - 55.6 = 44.4)

Step 1: Convert the given mass to moles.

moles Ca = given mass Ca / molar mass Ca

moles = 55.6 / 40 = 1.39 moles

mol S = specific mass S / molar mass S

mol = 44.4 / 32 = 1.39 mol

Step 2: Divide the molar ratio of each molar value by the smallest number of moles calculated.

For Ca = 1.39 / 1.39 = 1

For S = 1.39 / 1.39 = 1

The ratio of Ca : S = 1:1

Hence the empirical formula of the given compound will be CaS.

Learn more about empirical formula here : brainly.com/question/1496676

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Which of the outer planets would you most likely visit? Why? What would you see on your visit?
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Brainliest answer?

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