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3 years ago

A 1kg dictionary is resting on a table that is 1.5m high. How much potential energy

Physics

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

Potential energy = 14.7 Joules.

Explanation:

Given the following data;

Mass, m = 1kg

Height, h = 1.5m

We know that acceleration due to gravity is equal to 9.8m/s²

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

$P.E = mgh$

Where, P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

$P.E = mgh$

Substituting into the equation, we have;

$P.E = 1*9.8*1.5$

P.E = 14.7 Joules.

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A man pushes an 250-N crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with th

mel-nik [20]

Answer:

6495.19 Joule

Explanation:

F = Weight of the crate = 250 N

d = Distance the cart is pushed = 30 m

θ = Angle of inclination = 60°

The weight of the crate will be resloved into two components

Fdsinθ and Fdcosθ

Work done by the force of gravity is

W = Fdsinθ

⇒W = 250×30×sin60

⇒W = 6495.19 Joule

∴ The work done by the force of gravity is 6495.19 Joule

8 0

3 years ago

2. Determine the current in a 120-watt bulb plugged into a 120-volt outlet.

Sergio039 [100]

Answer:

1 ampere

Explanation:

Power = VI

V = voltage

I = current

Given

Power = 120 watts

V = 120 volts

Therefore

120 = 120 x I

Divide both sides by 120

120/120 = 120/120 x I

1 = I

I = 1 ampere

8 0

3 years ago

Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to

Tom [10]

To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.

5 0

3 years ago

A car moving due east increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s. How far, in meters, did the car travel whil

omeli [17]

During the period of constant acceleration, the car's average speed is (1/2) (16 + 32) = 24 m/s. At that average speed, it covers 240 meters in 10 seconds.

3 0

3 years ago

a bullet is fired horizontally with a speed of 524 m/s from a height of 22m above the ground. calculate where it will hit the gr

lara31 [8.8K]

Given data:

* The height of the bullet is 22 m.

* The speed of bullet in the horizontal direction is 524 m/s.

Solution:

By the kinematics equation, the time taken by the bullet to reach the ground is,

$h=u_yt+\frac{1}{2}gt^2$

where u_y is the vertical velocity component, t is the time taken to reach the ground, g is the acceleration due to gravity, and h is the height of the bullet,

Substituting the known values,

$\begin{gathered} 22=0+\frac{1}{2}\times9.8\times t^2 \\ t^2=\frac{22\times2}{9.8} \\ t^2=4.49 \\ t=2.12\text{ s} \end{gathered}$

Thus, the time taken by the bullet to reach the ground is 2.12 seconds.

By the kinematics equation for the horizontal motion, the horizontal range of the bullet is,

$R=u_xt+\frac{1}{2}at^2$

where u_x is the horizontal component of the velocity, a is the acceleration along the horizontal direction, t is the time taken to reach the ground and R is the horizontal range,

Substituting the known values,

$\begin{gathered} R=524\times2.12+0 \\ R=1110.9\text{ m} \end{gathered}$

Thus, the horizontal range of the bullet is 1110.9 meters.

Hence, the bullet hit the ground at 1110.9 meters.

8 0

1 year ago