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4 years ago

How many grams of CO2 are in 2.1 mol of the compound?

2 answers:

8 0

1 mole of CO2 = 44 g CO2

2.1 mol CO2 x (44. g CO2/1 mole CO2) = 92.4 g <span> grams of CO2 are in 2.1 mol of the compound</span>

madam [21]4 years ago

5 0

Molar mass CO2 = 12 + 16 x 2 => 44.0 g/mol

1 mol ----------- 44.0 g
2.1 mol --------- ( mass CO2)

mass CO2 = 2.1 x 44.0 / 1

mass CO2 = 92.4 / 1

= 92.4 g of CO2

hope this helps!

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The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at

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Answer:

the solubility of CaCO3 is 0.015g/l 25 °C

is favored at equilibrium

Explanation:

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?

solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)

CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)

in partial dissociation , we can say

2.25x 10^-8= $Ca^{2+} +CO^{2-}_{3} }$

let Ca^2+=CO3^-2=S

2.25x10^-8=S*S

S^2=2.25x10^-8

S=0.00015mol/L

Converting that to g/l

the relative molecular mass of CaCO3=100g/mol

0.00015*100g/mol

0.015g/l

the solubility of CaCO3 is 0.015g/l @room temperature

is favored at equilibrium

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