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2 years ago

What are some ways the stars in the photo could be grouped or classified

1 answer:

8 0

Astronomers classify stars according to their physical characteristics. Characteristics used to classify stars include color, temperature, size, composition, and brightness. Stars vary in their chemical composition.

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10 points Which of these is the best example of heat transfer by radiation? *

insens350 [35]

Answer:

a) A satellite is warmed by sunlight.

Explanation:

Heat transfer by radiation mostly involves heat gain or heat loss from the Sun. In this case, Option A is the only option where sunlight is involved so it is the best example of heat transfer by radiation.

3 0

2 years ago

Calculate the percent composition of the following: A. VO3 B. V2O5

tino4ka555 [31]

A) Answer is: 51.48% V and 48.52% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(VO₃) = 50.94 + 3 · 16.

Ar(VO₃) = 98.94; molecular weight of vanadium (VI) oxide.

ω(V) = Ar(V) ÷ Ar(VO₃) · 100%.

ω(V) = 51.48%; the percent composition of vanadium.

ω(O) = 100% - 51.48%.

ω(O) = 48.52%; the percent composition of oxygen.

B) Answer is: 67.80% V and 32.20% O.

Ar(V) = 50.94; atomic weight of vanadium.

Ar(O) = 16; atomic weight of oxygen.

Ar(V₂O₅) = 2 · 50.94 + 5 · 16.

Ar(V₂O₅) = 149.88; molecular weight of vanadium (V) oxide.

ω(V) = 2 · Ar(V) ÷ Ar(V₂O₅) · 100%.

ω(V) = 67.80%; the percent composition of vanadium.

ω(O) = 100% - 67.80%.

ω(O) = 32.20%; the percent composition of oxygen.

4 0

3 years ago

Gaseous methane ch4 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o . suppose 1.44

Usimov [2.4K]

The balanced equation for the above reaction is;
CH₄ + 2O₂ ---> CO₂ + 2H₂O
Stoichiometry of CH₄ to O₂ is 1:2
The number of methane moles present - 1.44 g/ 16 g/mol = 0.090 mol
Number of oxygen moles present - 9.5 g/ 32 g/mol = 0.30 mol
If methane is the limiting reagent,
0.090 moles of methane react with 0.090x 2 = 0.180 mol
only 0.180 mol of O₂ is required but 0.30 mol of O₂ has been provided therefore O₂ is in excess and CH₄ is the limiting reactant.
Number of moles of water that can be produced - 0.180 mol
Therefore mass of water produced - 0.180 x 18 g/mol = 3.24 g
Therefore mass of 3.24 g of water can be produced

6 0

2 years ago

Read 2 more answers

What happens to the rate of a reaction as the reaction progresses?

d1i1m1o1n [39]

Answer:

Explanation:

The rate of a reaction decreases as time progresses. ... If the amount of reactant particles is decreasing as the reaction progresses, then the chance of successful collisions must also decrease, and ultimately when all the reactant particles have reacted, the reaction must stop and the rate become zero.

7 0

3 years ago

Read 2 more answers

Write chemical equations to show how the following bases react with water to produce hydroxide ions:

77julia77 [94]

OCH₃⁻ + H₂O → CH₃OH (methanol) + OH⁻ (hydroxide)

here, the methoxide ion acted as a base, by bonding with the hydrogen atom released by water to form methanol and hydronium ion

ClO⁻ + H₂O → HClO + OH⁻ (hydroxide)

The Hypochlorite ion bonded with the proton released by water, to form Hypochlorous acid and hydronium ion

7 0

3 years ago