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postnew [5]
2 years ago
12

Complete the following math problem and round your answer to the correct number of significant figures. Explain why your answer

has that number of decimal places or significant figures.
12.65 + 11.2
Chemistry
1 answer:
BigorU [14]2 years ago
7 0

Answer:

file link http/www.openfree

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Help quick! Will mark brainlest!
Ivenika [448]

Answer: 10HSiCl3 + 15H2O → H10Si10O15 + 30HCl

Explanation:

6 0
2 years ago
A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g
svetoff [14.1K]

Answer:

The answer to your question is a) 51.07 g of NiBr₂   b) Nickel, 54 g

Explanation:

Data

mass of NiBr₂ = ?

mass if Ni = 67.8 g

mass of Br = 37.3 g

Balanced chemical reaction

                Ni  +  Br₂   ⇒   NiBr₂

Process

1.- Find the atomic mass of the reactants and the molar mass of the product

Ni = 59 g

Br = 79.9 x 2 = 159.8 g

NiBr₂ = 59 + 159.8 = 218.8 g

2.- Find the limiting reactant

theoretical yield  Ni/Br₂ = 59/159.8 = 0.369

experimental yield Ni/Br₂ = 67.8/37.3 = 1.81

The limiting reactant is Bromine because the experimental yield was lower than the theoretical yield.

3.- Calculate the mass of NiBr₂

                    159.8 g of Br₂ --------------- 218.8 g of NiBr₂

                      37.3 g of Br₂ --------------  x

                          x = (37.3 x 218.8) / 159.8

                          x = 8161.24/159.8

                          x = 51.07 g of NiBr₂

4.- Find the excess reactant

The excess reactant is Nickel

                59 g of Ni ---------------- 159.8 g of Br₂

                  x               ----------------  37.3 g of Br₂

                            x = (37.3 x 59)/159.8

                            x = 2200.7/159.8

                            x = 13.77 g of Ni

Excess Ni = 67.8 - 13.77

                 = 54 g

5 0
3 years ago
All of the following are examples of suspensions except what?:
artcher [175]
Dust particles in the air
6 0
2 years ago
Which of the following most influenced the changing nature of classification systems
Lyrx [107]
Hope I helped you enjoy your day

5 0
2 years ago
Read 2 more answers
What is the quantum number set of the ground-state electron that is found in lithium (Li) but not in helium (He)?
statuscvo [17]
The electron configuration of lithium atom is: Li:[He]2s^1

The number "2" is the value of the principal quantum number "n". Letter "s" is associated with the value of secondary quantum number "l" and it is equal to zero. The value of "m" (or magnetic quantum number) is zero too. The quantum number set for the highest energy electron will be (2, 0, 0, 1/2).
3 0
3 years ago
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