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Sveta_85 [38]
2 years ago
11

Calculate the total pressure in a 10.0 liter flask at 27°C of a sample of gas that contains 6.0 grams of hydrogen, 15.2 grams of

nitrogen, and 16.8 grams of helium.
Chemistry
1 answer:
motikmotik2 years ago
7 0

Answer:

The total pressure is 27.8 atm

Explanation:

From the ideal gas equation,

PV = nRT

P (total pressure) = nRT/V

n (total moles of gases) = (6/1 moles of hydrogen) + (15.2/14 moles of nitrogen) + (16.8/4 moles of helium) = 6+1.1+4.2 = 11.3 moles

R = 0.082057L.atm/gmol.K, T = 27°C = 27+273K = 300K, V = 10L

P = 11.3×0.082057×300/10 = 27.8 atm

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How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
3 years ago
Water freezes at 32 degrees
olga55 [171]

Answer:

Fahrenheit

Explanation:

7 0
2 years ago
Read 2 more answers
A calorimeter measures the Choose... involved in reactions or other processes by measuring the Choose... of the materials Choose
yuradex [85]

Answer:

heat; temperature; surrounding; insulated.

Explanation:

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Some of the components that make up a simple calorimeter are; thermometer, an interior styrofoam cup, an exterior styrofoam cup, cover, etc.

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3 0
3 years ago
Find the pH. What are the pH values for the following solutions? (a) 0.1 M HCl (b) 0.1 M NaOH (c) 0.05 M HCl (d) 0.05 M NaOH
slega [8]

Answer:

(a) pH=1

(b) pH=1.3

(c) pH=13

(d) pH=12.7

Explanation:

Hello,

In this case, we define the pH in terms of the concentration of hydronium ions as:

pH=-log([H^+])

Which is directly computed for the strong hydrochloric acid (consider a complete dissociation which means the concentration of hydronium equals the concentration of acid) in (a) and (c) as shown below:

(a)

[H^+]=[HCl]=0.1M

pH=-log(0.1)=1

(b)

[H^+]=[HCl]=0.05M

pH=-log(0.05)=1.3

Nevertheless, for the strong sodium hydroxide, we don't directly compute the pH but the pOH since the concentration of base equals the concentration hydroxyl in the solution:

[OH^-]=[NaOH]

pOH=-log([OH^-])

pH=14-pOH

Thus, we have:

(b)

pOH=-log(0.1)=1\\pH=14-1=13

(d)

pOH=-log(0.05)=1.3\\pH=14-1.3=12.7

Best regards.

5 0
3 years ago
How many Grams would he present if 1 mole sample of sodium were collected?
Zigmanuir [339]
Mass = moles x Mr
So in this case the moles =1
And the Mr equals =11
So you would do - 11x1= 11grams
8 0
3 years ago
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