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Korolek [52]
3 years ago
12

A laser beam enters a 12.0 cm thick glass window at an angle of 33.0° from the normal. The index of refraction of the glass is 1

.41. At what angle from the normal does the beam travel through the glass? How long does it take the beam to pass through the plate?
Physics
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

The time is 0.563 ns.

Explanation:

Given that,

Index of refraction of glass = 1.41

Distance = 12.0 cm

Angle = 33.0°

We need to calculate the refraction angle

Using Snell's law

n_{1}\sin\theta=n_{r}\sin\theta

put the value into the formula

1\times\sin33=1.41\sin\theta

\sin\theta=\dfrac{1\times\sin33}{1.41}

\theta=22.71^{\circ}

We need to calculate the velocity of beam in glass

Using formula of velocity

v=\dfrac{c}{n}

Put the value into the formula

v=\dfrac{3\times10^{8}}{1.41}

v=2.13\times10^{8}\ m/s

We need to calculate the time

Using formula of distance

v=\dfrac{d}{t}

t=\dfrac{12.0\times10^{-2}}{2.13\times10^{8}}

t=5.63\times10^{-10}\ sec

t=0.563\times10^{-9}\ sec

t=0.563\ ns

Hence, The time is 0.563 ns.

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