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goldenfox [79]
3 years ago
7

The units we use to measure the sound intensity level are _____.

Physics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

decibels (dB)

Explanation:

The sound intensity level is a quantity derived from the sound intensity.

The intensity of a wave is defined as the power of the source of the wave divided by the area through which the power of the wave is spread, mathematically:

I=\frac{P}{A}

where

P is the power of the source

A=4\pi r^2 is the surface area over which the wave spreads (assuming that the wave propagates in all directions, it corresponds to the surface area of a sphere of radius r, where r is the distance between the source of the wave and the observer)

For sound waves, the intensity is often expressed using another unit, called decibel (dB), defined as follows:

\beta(dB)=10Log_{10}(\frac{I}{I_0})

where

\beta is the sound intensity level in decibels

I is the intensity of the sound wave

I_0=1\cdot 10^{-12} W/m^2 is the threshold intensity of a sound that a person can normally hear.

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The ratio of the output work to input force is the _ of the machine ?
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<h3><u>Answer;</u></h3>

Mechanical advantage

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Now, find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 11. Then div
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Explanation:

When pH of the solution is 11.

..(1)

At pH = 11, the concentration of ions is .

When the pH of the solution is 6.

..(2)

At pH = 6, the concentration of ions is .

On dividing (1) by (2).

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is .

Difference between the ions at both pH:

This means that Hydrogen ions in a solution at pH = 7 has ions fewer than in a solution at a pH = 6

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What type of bond connects the atoms in a molecule of Carbon dioxide gas (CO2)?
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Covalent Bond

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7 0
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The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V , which charges a capacitor
aksik [14]

Answer:

The capacitance of the capacitor is 1.85*10^{-5}F

Explanation:

To solve this exercise it is necessary to apply the concepts related to Power and energy stored in a capacitor.

By definition we know that power is represented as

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E= Energy

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Solving to find the Energy we have,

E = P*t

Our values are:

P = 1*10^5W

t = 12*10^{-6}s

Then,

E= (1*10^5)(12*10^{-6})

E = 1.2J

With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

E=\frac{1}{2}CV^2

Solving for C=

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Therefore the capacitance of the capacitor is 1.85*10^{-5}F

7 0
3 years ago
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