Answer:
work is shown and pictured
Answer:
After the sale there were 15 cars and 5 motorcycles
Step-by-step explanation:
c=cars originally
m=motorcycles originally
c=2m (2 times the cars than motorcycles)
(c+1) bought 1 car after sale
sold 1 motor cycle (m-2) after sale
(c+1) = 3(m-2) (3 times more cars than motorcycles)
(c+1) = 3(m-2)
distribute
c+1 = 3m-6
substitute c =2m
2m +1 = 3m-6
subtract 2m from each side
2m+1-2m = 3m-6-2m
1 = m-6
add 6 to each side
1+6 = m-6+6
m=7
c = 2m
c = 2(7) =14
c=14
Originally there were 7 motorcycles and 14 cars
After the sale c+1 = 15, m-2 = 5
there were 15 cars and 5 motorcycles
Hello from MrBillDoesMath!
Answer:
975/1000
Discussion:
.975 = 975/1000
Thank you,
MrB
So 8x^2+8x+8-(-9x^2+2x+5) is going to be
8x^2+9x^2+8x-2x+8-5
Giving you
17x^2+6x+3