If you're holding the apple at your waist, lift it to your mouth.
Potential energy relative to any level is proportional to its height
above that level. Increase that height, and you've increased the
potential energy.
Since energy is conserved ... it never magically appears or
disappears ... you need to tell where that extra energy for the
apple came from.
It's exactly the work you did ... the force of your muscles acting
through the distance you raised the apple ... that became the
additional potential energy that the apple gained.
Mass of Potassium : 116.1 g
<h3>Further explanation</h3>
Given
38.7% potassium in Potassium nitrate
300 g of KNO3
Required
mass of potassium
Solution
%mass of element = (mass of an element in 1 mole of compound/mass of 1 mole compound) x 100%
mass of K(potassium) in 300 g KNO3 :
= 38.7% x 300 g
= 116.1 g
Answer:
cheese and bread
Explanation:
2 bread 1 cheese = cheese sandwich
In a chemical equilibrium, the forward and reverse reactions occur at equal rates, and the concentrations of products and reactants remain constant. A catalyst speeds up the rate of a chemical reaction, but has no effect upon the equilibrium position for that reaction.
Answer:
No, you can not calculate the solubility of X in water at 17 0C.
Explanation:
Solubility refers to the amount of a substance that dissolves in 1000 L of water.
To calculate the solubility of a solute in water, all the water is evaporated and the solid is carefully collected, washed, dried and weighed. The mass of solid obtained can now be used to calculate the solubility of the solute in water as long as there was no loss in mass of solid during the experiment.
In this case, the student threw away part of the solid that precipitated. As a result of this, the mass of solid obtained at the end of the experiment is not exactly the total mass of solute that dissolved in the solvent. Hence, the solubility of X in water at 17 0C can not be accurately calculated.