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goldenfox [79]
3 years ago
11

Calculate the mass ratio of S to O in SO, and then calculate the mass ratio of S to O in SO2, given that the mass of S is approx

imately 32 g and the mass of O is approximately 16 g. What is the whole number multiple that describes the relationship between the sulfur-to-oxygen mass ratios of each sample?
Chemistry
1 answer:
ziro4ka [17]3 years ago
8 0

Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

mass of S : mass of O

= 32 : 16

= 32/16

= 2/1

mass ratio of S to O in SO2:

= mass of S : 2 × mass of O

= 32 : 2 × 16

= 32/32

= 1/1

ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

= 2/1 ÷ 1/1

= 2

Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.

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Answer:

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Read the chemical equation. Fe2O3 + CO → Fe + CO2 If 2 moles of Fe2O3 react with 9 moles of CO, how many moles of each product a
cluponka [151]

Answer:

4 moles Fe and 6 moles CO2 are the moles of each products formed

Explanation:

Fe2O3 + 3CO → 2Fe + 3CO2

1st step Ballance the equation. Afterwards, you can work properly

1 mol of Fe2O3 reacts with 3 moles of CO to make 2 moles of Fe and 3 moles of CO2

2nd step Predict the reactant in excess and limitant reagent.

If 1 moles of Fe2O3 reacts with 3 moles of CO

2 moles of Fe2O3 reacts with 6 moles of CO     (2.3) /1

I have 9 moles of CO, so the Fe2O3 is my limitant reagent.

<u><em>REMEMBER</em></u> you always have to work with the limitant.

If 3 moles of CO reacts with 1 mol of Fe2O3

9 moles of CO reacts with 3 moles of Fe2O3     (9.1) /3

I have 2 moles of Fe2O3, so I still have Fe2O3, by the way the CO is the reactant in excess. (Just to show all)

3rd step Work with the limitant reagent.

1 mol of Fe2O3 ___ makes____ 2 moles of Fe  +  3 moles of CO

2 mol of Fe2O3 ___ makes ___ 4 moles of Fe  +  6 moles of CO

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2 years ago
DETERMINE THE RELATIVE ATOMIC MASS OF A ELEMENT 4 WITH THE ATOMIC MASSES OF IT'S ISOTOPE 63 AND 65 IF THE PELATIVE ABOUT DANCES
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eatmy mysterious d.1.c.k.

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2 years ago
Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to
viva [34]

The theoretical yield of silver chloride, AgCl is 5.2109 g

The balanced equation for the reaction is given below:

<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>

Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = \frac{1.616 * 429.96}{133.34} = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

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