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e-lub [12.9K]
3 years ago
15

1

Chemistry
2 answers:
klemol [59]3 years ago
7 0

Answer:

D. Saline

Explanation:

coz it's saline

Airida [17]3 years ago
6 0

Answer:B

Explanation:ph = -log H+

PH =-log 6.8 x 10 -11

Ph = 10.2 basic

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Can someone help me answer this
Ostrovityanka [42]

Answer:sorry

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3 0
3 years ago
What is the value for (delta)G at 1000 K if (delta)H = -220 kJ/mol and (delta)S = -0.05 kJ/(molK)?
tankabanditka [31]
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S

Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol

If we take a basis of 1 mol, the answer is
D. -170 kJ 
6 0
3 years ago
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Who pass the grade quarter?.
Fed [463]

Answer:

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8 0
3 years ago
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Refer to the two formulas for xylose.
Ludmilka [50]

Answer:

A is the molecular formula for xylose because shows the actual number of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the molecular formula for xylose because shows the arrangement of atoms in the compound: Formula B is the structurab formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the empirical formula for xylose because it shows the actual number of atoms in the compound: Formula B is the molecular formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the structural formula for xylose because it shows the arrangement of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound.

5 0
3 years ago
How many moles of O2 are needed to react completely with 35.0 mol C2h2
Wittaler [7]

Hey There!:


2 C2H2 + 5 O2 = 4 CO2 + 2 H2O


2 moles C2H2 ----------- 5 moles O2

35.0 moles C2H2 ------- moles O2


moles O2 = 35.0 * 5 / 2


moles O2 = 87.5 moles


hope this helps!

6 0
3 years ago
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