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e-lub [12.9K]
3 years ago
15

1

Chemistry
2 answers:
klemol [59]3 years ago
7 0

Answer:

D. Saline

Explanation:

coz it's saline

Airida [17]3 years ago
6 0

Answer:B

Explanation:ph = -log H+

PH =-log 6.8 x 10 -11

Ph = 10.2 basic

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What might be a scientific question
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A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

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M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

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0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

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Total volume of solution = 160.0 mL + 1086.79 mL

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Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

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Thus, the pH of the solution is, 5.24

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How many particles are in 2.0 moles of CH4
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