All categories

3 years ago

Consider this question: What is the molarity of HCL if 35.23 mL of a solution of HCL contains 0.3366 g of HCL?

Chemistry

1 answer:

Crazy boy [7]3 years ago

6 0

Answer: The molarity of HCl solution is 0.262 M

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of HCl = 0.3366 g

Molar mass of HCl = 36.5 g/mol

Volume of the solution = 35.23 mL

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.3366g\times 1000}{36.5g/mol\times 35.23mL}\\\\\text{Molarity of HCl}=0.262M$

Hence, the molarity of HCl solution is 0.262 M.

You might be interested in

When you have dominant allele T, recessive for t, T for tall and t for short, what will be phenotype for Tt?

Dmitry_Shevchenko [17]

Answer:

TT and Tt genotypes both expressed the tall phenotype because the T is dominant to t. Only the tt genotype expressed the short phenotype.

Explanation:

Hope this helped!

8 0

3 years ago

What is the average speed of a skateboarder who travels 20 km in 2 hours

astra-53 [7]

Answer:

the average speed is 10 km/hr

8 0

3 years ago

A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the value of standar

Akimi4 [234]

Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

In a standard cell,

the reduction half cell reaction is :

$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$

The oxidation half ell reaction :

$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$

Thus the complete reaction of the cell is :

$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$

$E^0$ cell = $E_R - E_L = 0.00 \ \text{volts}$

7 0

3 years ago

What is the unit of measure for energy? watt newtons joules meters per second

egoroff_w [7]

Answer:

c. Joules

Explanation:

I went over this already

3 0

3 years ago

Read 2 more answers

P-fluoroanisole reacts with sulfur trioxide and sulfuric acid. Draw the major product of this substitution reaction; if applicab

Ipatiy [6.2K]

Answer: (Structure attached).

Explanation:

This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.

The aromatic ring in p-fluoroanisole has two sustituents, an halogen and a methoxy group, which are ortho-para directing substituents.

Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using sulfur trioxide as an electrophile (very reactive).

The reaction occurs in three steps:

The attack on the electrophile forms the sigma complex.
The loss of a proton regenerates an aromatic ring.
The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).

Normally, a mixture of ortho-para substituted products would be obtained. However, since both para positions are occupied, only the ortho substituted product is obtained here.

8 0

3 years ago