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Black_prince [1.1K]
3 years ago
10

Hii pls help me!! even if u know how to do one, it's okk anything helps ​

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Explanation:

a) HNO2(aq) = HNO3(aq) + H2O(l) +NO(g)

b) SoCl2 (l) + H2O (l) = So2(g) + 2HCl(aq)

c) CH4 (g) + 2O2(g) = Co2 (g) + 2H2O(g)

d) 3CuO(s) + 2NH3 (g) = 3Cu(s) + 3H2O (l) + N2(g)

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What would you predict to be the valence number and oxidation number of tin?
murzikaleks [220]

Answer:

Tin exists in two oxidation states, +4 and +2. Elemental tin is readily oxidized to the dipositive ion in acidic solution, but this Sn2+ ion is converted to the Sn4+ ion by many mild oxidizing agents, including elemental oxygen. Oxidation under alkaline conditions normally gives the tetrapositive (Sn4+) state.

8 0
3 years ago
1.80x1024 molecules of CO2 is equal to how many grams?
olga nikolaevna [1]

Answer:

131.5177 grams

Explanation:

You divide by Avogadro's number to turn it into moles then multiply by molar mass.

7 0
3 years ago
H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
3 years ago
A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo
Goshia [24]

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

8 0
3 years ago
What is the principal difference between a strong and weak acid?
jekas [21]

a strong acid fully dissociates in water to form H+ ions in water while a weak acid only partially dissociates to form H+ ions in water

4 0
3 years ago
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