Answer:
Value of 
is 0.090.
Explanation:
Initial molarity of 
= 
= 0.0700 M
Construct an ICE table corresponding to the combustion reaction of carbon to determine
I (M): - 0.0700 0
C (M): - -x +2x
E (M): - 0.0700-x 2x
So, ![K_{c}=\frac{[CO]^{2}}{[O_{2}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BCO%5D%5E%7B2%7D%7D%7B%5BO_%7B2%7D%5D%7D)
, where [CO] and ![[O_{2}]](https://tex.z-dn.net/?f=%5BO_%7B2%7D%5D)
represents equilibrium concentration of CO and respectively.
Here, ![[CO]=2x=0.060](https://tex.z-dn.net/?f=%5BCO%5D%3D2x%3D0.060)
⇒x = 0.030
So, = 0.0700-x = (0.0700-0.030) = 0.040
Hence, 
Most stores have 2 rows of aisles facing parallel to each other- wait, why are you even asking this question?
Answer:
$25,985.25
Explanation:
Assuming it is compounded annually.
The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .
The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.
The thermochemical equation for the combustion of benzene is;
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol
We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.
Learn more: brainly.com/question/13164491
