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zlopas [31]
2 years ago
10

Does this chemical equation satisfy the Law of Conservation of Mass? CS 2 +O 3 -->CO 2 +SO 2

Chemistry
1 answer:
makkiz [27]2 years ago
4 0

Answer:

<em><u>No it doesn't satisfy the Law of Conservation of Mass</u></em>.

<u>Explanation</u><u>:</u>

<em><u>A balanced chemical equation obeys the law of conservation of mass. </u></em>

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How often do most coastlines on Earth experience two high tides and two low tides?
Elza [17]

Answer:

24 hours and 50 minutes

Explanation:

Because the Earth rotates through two tidal “bulges” every lunar day, coastal areas experience two high and two low tides every 24 hours and 50 minutes. High tides occur 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from high to low, or from low to high.

4 0
2 years ago
Which of the following is a characteristic of an S wave?
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Though S waves can travel through solids, they cannot travel through liquids.

HOPE THIS HELPS!!!

3 0
2 years ago
What is the ratio between the coefficients of any two substances in a balanced equation?
ICE Princess25 [194]
In a balanced chemical equation, we have two numbers that indicate two different factors. The definitions of these numbers are as follows:

1- Molar ratio: This ratio represents the ratio between the number of moles of any two substances in the balanced equation

2- The coefficients in the balanced chemical equation: These numbers represent the numbers of particles of each of the substances taking place in this chemical equation.
4 0
3 years ago
How many moles are in 3.46 g of chromium?
Bezzdna [24]

Answer:

0.06654345229738384 moles of chromium.

6 0
3 years ago
Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i
swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg  

7 0
2 years ago
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