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zlopas [31]
2 years ago
10

Does this chemical equation satisfy the Law of Conservation of Mass? CS 2 +O 3 -->CO 2 +SO 2

Chemistry
1 answer:
makkiz [27]2 years ago
4 0

Answer:

<em><u>No it doesn't satisfy the Law of Conservation of Mass</u></em>.

<u>Explanation</u><u>:</u>

<em><u>A balanced chemical equation obeys the law of conservation of mass. </u></em>

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from the equation 2PbO + C = 2Pb + CO2, detemine which one is reactant is oxidised and which is reduced.​
ss7ja [257]

Answer:

Explanation:

C is oxidised because C up to C+4

PbO is reduced because PbO from Pb2+ down to Pb0

6 0
2 years ago
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Whats the unit for mass
sesenic [268]

Answer:

The unit for mass is the kilogram (Kg).

Explanation:

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The combustion of ________ has added great quantities of carbon dioxide to the atmosphere. Group of answer choices
forsale [732]

Answer:

Fossil fuels.

Explanation:

A fossil fuel is a fuel obtained from nature such as crude oil, coal, wood etc. The burning of fossil fuels releases tremendous amounts of carbon IV oxide into the environment causing a myraid of environmental problems paramount among them is global warming with its attendant consequences.

7 0
3 years ago
Which is the correct Lewis structure for carbon monoxide?
LuckyWell [14K]
<span>The Lewis structure for CO has 10 valence electrons. For the CO Lewis structure you'll need a triple bond between the Carbon and Oxygen atoms in order to satisfy the octets of each atom while still using the 10 valence electrons available for the CO molecule.</span>
7 0
2 years ago
How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
2 years ago
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