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Setler [38]
3 years ago
8

A power supply maintains a potential difference of 52.3 V 52.3 V across a 1570 Ω 1570 Ω resistor. What is the current in the res

istor?
Physics
1 answer:
irakobra [83]3 years ago
6 0

Answer:

0.033 A

Explanation:

Current: This can be defined as the rate of flow of electric charge in a circuit.

The S.I unit of current is Ampere (A)

From Ohm's law.

V = IR ............................ Equation 1

Where V = Potential difference, I = current, R = resistance.

Making I the subject of the equation,

I = V/R................... Equation 2

Given: V = 52.3 V, R = 1570 Ω

Substitute into equation 2

I = 52.3/1570

I = 0.033 A.

Hence the current in the resistor = 0.033 A

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Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño
Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial  x-component [m/s]\\t= time [s]

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

y=(v_{y} )_{o}*t-0.5*g*t^{2}  \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

8 0
3 years ago
What is the best reason to talk to an adult if you are feeling symptoms of a mental disorder? They can help you find services in
vitfil [10]
<span>They can help you find services in your community.</span>
5 0
4 years ago
Read 2 more answers
Suppose a tidal basin is 6 m above the ocean at low tide and that the area of the basin is 5×107 m2. Estimate the gravitational
Neko [114]

Answer:

Potential energy will be 176.58\times 10^{11}j          

Explanation:

We have given the height of the basin is h = 6 m

Area of the basin A=5\times 10^7m^2

Volume V=area \times height=5\times 10^7\times 6=30\times 10^7m^3

Density \rho =1000kg/m^3

We know that mass is given by m=\rho V=1000\times 30\times 10^7=3\times 10^{11}kg

We know that potential energy is given by E=mgh=3\times 10^{11}\times 9.81\times 6=176.58\times 10^{11}j

3 0
3 years ago
If the temperature of an iron sphere is increased
lesya692 [45]
<h2>Answer: its density will decrease</h2>

By increasing the temperature of the iron sphere, its volume will increase (due to the material of which it is composed), this is a phenomenon known as<em> thermal dilation</em>. However, the mass of the sphere will remain the same.

On the other hand, density D is a characteristic property of substances and materials and is defined as the relationship between the mass m and volume V of a specific substance or material, as shown below:

D=\frac{m}{V}

This means <u>density is inversely proportional to volume</u>. Therefore, increasing the temperature of the iron sphere, its volume will be increased and <em><u>its density will be decreased</u></em>.

5 0
3 years ago
A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

Q_B=9\times10^-6C

d_A = 1+x cm

d_B=x cm

k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

#SPJ4

3 0
2 years ago
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