All categories

3 years ago

Can someone answer this multiple choice, and ignore the one I accidentally touched

Physics

2 answers:

Valentin [98]3 years ago

8 0

Answer:

20N

Explanation:

Force= Mass*Acceleration

Force=10kg*2m/s^2

Force=20N

Mice21 [21]3 years ago

5 0

Answer:

20 N

Explanation:

Newton's Second Law of Motion gives us the relationship between force, mass, and acceleration:

F = ma

In this problem, we are given the mass of the body and its acceleration.

m = 10 kg
a = 2 m/s²

Substitute these values into the formula to find the force acting on the body.

F = (10 kg)(2 m/s²)
F = 20 kg · m/s²
F = 20 N

The units for force is in Newtons, so the answer is the second option.

You might be interested in

Which of these experiments would make use of qualitative data

7nadin3 [17]

It has to due with numbers so I would say the last one!

5 0

3 years ago

Read 2 more answers

The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth

ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

$\frac{P_{1} }{\\P_2}$ = $\frac{density * g * h_1}{density * g * h_2}$

So $\frac{39}{P_2}$ = $\frac{3}{9}$

Or P₂= 39 * 3 = 117 kPa

5 0

3 years ago

A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber

Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

$V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}$

Now calculate the bouyant force acting on the lead

$F_L = Vpg$

$F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N$

This force will act in upward direction

Gravitational force on the lead due to its mass will act in downward direction

Hence the difference of this two force

$T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N$

If V is the volume submerged in the water then bouyant force on the bobber is

$F_B=V'pg$

Equate bouyant force with the tension and gravitational force

$F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}$

Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$

= $\large\boxed{4.52 \%}$

7 0

3 years ago

An elevator manufacturing company is stress-testing a new elevator in an airless test shaft. The elevator is traveling at an unk

devlian [24]

Answer:

3.192 m/s

Explanation:

t = Time taken = 0.900 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 1.1 meters

a = Acceleration due to gravity = 9.81 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1.1-\frac{1}{2}\times 9.81\times 0.9^2}{0.9}\\\Rightarrow u=-3.192\ m/s$

Velocity of the elevator when it snapped is 3.192 m/s

4 0

3 years ago

Why do yall like Biden

stealth61 [152]

“We LoVeEe BiDeN bEcAuSe hIs HeAlThCaRe iSn’T FrEeEeE!”

6 0

3 years ago

Read 2 more answers