Answer:
The turbine produces <u>955.53 KW</u> power.
Explanation:
Taking the turbine as a system. Applying Law of Conservation of Energy:
m(h₁ - h₂) - Heat Loss = P
where,
m = mass flow rate of steam = 1.31 kg/s
h₁ = enthalpy at state 1 (120 bar and 508°C)
h₂ = enthalpy at state 2 (50 KPa and x = 0.912)
Heat Loss = 225 KW
P = Power generated by turbine = ?
First, we find h₁ from super steam tables:
At,
T = 508°C
P = 120 bar = 12000 KPa = 12 MPa
we find that steam is in super-heated state with enthalpy:
Due to unavailibility of values in chart we approximate the state to 500° C and 12.5 MPa:
h₁ = 3343.6 KJ/kg
Now, for state 2, we have:
P = 50 KPa and x = 0.912
From saturated steam table:
h₂ = hf₂ + x(hfg₂) = 340.54 KJ/kg + (0.912)(2304.7 KJ/kg)
h₂ = 2442.4 KJ/kg
Now, using values in the conservation equation:
(1.31 kg/s)(3343.6 KJ/kg - 2442.4 KJ/kg) - 225 KW = P
<u>P = 955.53 KW</u>
