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pav-90 [236]
4 years ago
14

A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 25

kPa in the condenser and a turbine inlet temperature of 700°C. The boiler is sized to provide a steam flow of 50 kg/s. Determine the power produced by the turbine and consumed by the pump. Use steam tables.

Engineering
2 answers:
Maru [420]4 years ago
6 0

Answer:

power produced by turbine = 79656.15 KW

pump work =227.57 KW

Explanation:

here At T1 = 700 C and P1 = 4 Mpa, from steam tabel : h1 =3906.41 KJ/Kg and s1 = 7.62 KJ/Kg.K

now s1 = s2 = 7.62 KJ/Kg.K as 1-2 is isentropic

so at P2 = 20 Kpa and s2 = 7.62 KJ/Kg.K , fom steam table : h2 = 2513.33 KJ/Kg

power produced by turbine = m.( h1 - h2) = 57.18 x ( 3906.41 - 2513.33) = 79656.15 KW

at P3 = 20 Kpa, 3 = vf = 0.001 m^3/kg

so pump work = v3.dP = 57.18 x 0.001 x ( 4000 - 20) =227.57 KW

chubhunter [2.5K]4 years ago
3 0

Answer:

PT = 70 000kw

Pp = 202.4kw

Explanation:

The full details of the explanation is attached.

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8 0
3 years ago
Read 2 more answers
At any given state the specific internal energy of a gas is always greater its specific enthalpy. a)True b) False
IgorC [24]

Answer:

(b)False

Explanation:

We know that specific  Internal energy of gas u=C_vT

      and specific enthalpy of gas h=C_pT

If we take the case of air we know that

C_v=0.707 KJ/Kg=K  , C_p=1.005 KJ/Kg=K

If we take A fixed temperature T=300 K

so    u=212.1 KJ/ kg   ,h=301.5 KJ/kg

So we can say that specific enthaply of gas is always greater than its specific   internal energy.

                                 

     

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3 years ago
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4 years ago
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Answer:

wool, rubber, and plastic

Explanation:

5 0
3 years ago
Because of its high dielectric strength, SF6 (sulfur hexafluoride) gas is widely used as an insulator and a dielectric in HV app
Mars2501 [29]

Answer:

5.31 × 10⁻⁴⁰ Fm²

Explanation:

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P = (N/NA)RT where P = pressure = 1 atm = 1.013 × 10⁵ Pa, N = number of molecules of SF6 per unit volume, NA = Avogadro's constant = 6.022 × 10²³ /mol, R = molar gas constant = 8.314 J/mol-K and T = room temperature = 25° = 273 + 25 = 293 K

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= 6.100286 × 10²⁸ Pa/mol ÷ (2436.002 J/mol)

= 0.0025 × 10²⁸ molecules/m³

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So,

α = (ε - 1)3ε₀/[(ε + 2)N]

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α = 0.00531 × 10⁻³⁷ Fm²

α = 5.31 × 10⁻⁴⁰ Fm²

4 0
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