The question is incomplete, the complete question is;
Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane? product. A) The terminal alkyne is more stable than the internal alkyne and is naturally the favored B) The terminal alkyne is not favored in this reaction. C) The resonance favors the formation of the terminal rather than internal alkyne. D) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Answer:
E) The positions of the Cl atoms induce the net formation of the terminal alkyne.
Explanation:
In this reaction, sterric hindrance plays a very important role. We know that sodamide is a strong base, it tends to attack at the most accessible position.
The first deprotonation yields an alkene. The strong base attacks at the terminal position again and yields the terminal alkyne. Thus the structure of the dihalide makes the terminal hydrogen atoms most accessible to the base. Hence the answer.
Answer:
See the answer below.
Explanation:
Fire has three major components:
- Heat
- Smoke
- Gases ( in form of CO, CO2 etc)
If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.
If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.
<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>
Fdsddadgdsadgsd:
Fasdadasdfadsdfasdf asfsadafasdfasdffdaddad dads fdfgdfgfdg
Fdgdfgdfgdgfggggfg gdfgdfgd:
Fgdfgdfgdfgrdfhdf hdfgdfhdfh == fhdfgdfh /fhdgdg .
Answer : Methane 
does not has any resonating structures or isomers.
Explanation : Methane has tetrahedral geometry where all the valence bonds of carbon are satisfied with hydrogen atoms which are similar to each other. They also do not produce any lewis dot structure. Therefore, methane cannot have resonating structures.
