Question 1

A chemist must prepare 550 mL of hydrochloric acid solution with a pH of 1.60 at 25°C .

hammer [34]

<u>Answer:</u> The volume of concentrated hydrochloric acid solution is 1.73 mL

<u>Explanation:</u>

To calculate the hydrogen ion concentration of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 1.60

Putting values in above equation, we get:

$1.60=-\log [H^+]$

$[H^+]=10^{-1.60}=0.0251M$

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted HCl solution

We are given:

$M_1=8.0M\\V_1=?mL\\M_2=0.0251M\\V_2=550mL$

Putting values in above equation, we get:

$8.0\times V_1=0.0251\times 550.0\\\\V_1=\frac{0.0251\times 550}{8.0}=1.73mL$

Hence, the volume of concentrated hydrochloric acid solution is 1.73 mL

6 0

3 years ago

Hi! I need some solar system facts!

nikitadnepr [17]

The Solar System[b] is the gravitationally bound system of the Sun and the objects that orbit it, either directly or indirectly.[c] Of the objects that orbit the Sun directly, the largest are the eight planets,[d] with the remainder being smaller objects, the dwarf planets and small Solar System bodies. Of the objects that orbit the Sun indirectly—the natural satellites—two are larger than the smallest planet, Mercury.[e]

5 0

3 years ago

Read 2 more answers

Plutonium-236 is an alpha emitter with a half-life of 2.86 years. how long will it take for the 1.10 mg sample of pu−236 to deca

lawyer [7]

1.1 / 2 = .7 --> 2.86 yrs

.7 / 2 = .45 —> 5.72 yrs

.45 / 2 = .225 —> 8.58 yrs

.225 / 2 = .1125 —> 11.44 yrs

So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.

Hope this helps

5 0

3 years ago

What process describes how plants use air, water, and energy from the Sun to make their own food? A) water.

CaHeK987 [17]

D) the products of photosynthesis.

8 0

4 years ago

Read 2 more answers

Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answer

suter [353]

Answer: See below

Explanation:

To balance equations, you want to have the same amount of elements on the product and reactants side.

__Al+ __HCl→__AlCl₃+ __H₂

We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.

__Al+ 6HCl→__AlCl₃+ __H₂

Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.

__Al+ 6HCl→ 2AlCl₃+ 3H₂

All we have left is to fill in Al.

2Al+ 6HCl→ 2AlCl₃+ 3H₂

-----------------------------------------------------------------------------------------------------------------

__NaCl→ __Na+ __Cl₂

Since we have 2 Cl on the products, we must put 2 on the reactants.

2NaCl→ __Na+ 1Cl₂

With 2 NaCl, we can fill in Na.

2NaCl→ 2Na+ 1Cl₂

-----------------------------------------------------------------------------------------------------------------

__Na₂S+ __HCl→ __NaCl+ __H₂S

We see 2 Na on reactants, so we can put 2 on the products.

__Na₂S+ __HCl→ 2NaCl+ __H₂S

With 2 H and 2 Cl on the products, we can put a 2 at HCl.

1Na₂S+ 2HCl→ 2NaCl+ 1H₂S

7 0

3 years ago