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3 years ago

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9. Does a blackbody radiator emit light waves? Explain.

1 answer:

Yakvenalex [24]3 years ago

4 0

Answer:

"A blackbody is an object that absorbs all of the radiation that it receives(that is,it does not reflect any light,nor does it allow any light to pass through it and out the other side).The energy that the blackbody absorbs heats it up,and then it will emit its own radiation."

Explanation:

Risk*

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The equivalent capacitance of three capacitors, each of capacitance C connected at series

katrin2010 [14]

Answer:

In Series:

1/C = 1/c1 + 1/c2 + 1/c3

Explanation:

For equivalent,

1/C = 3/c

Ce = c/3

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3 years ago

A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’

scZoUnD [109]

A charged particle moving in a magnetic field experiences a force equal to:

$\vec{F}=q\vec{v}\times \vec{B}$

Thus, the magnitude of the force that the proton experiences is given by:

$F=qvBsin\theta$

The magnetic field is perpendicular to the proton's velocity, therefore, we have $\theta=90^\circ$ . Replacing the given values, we obtain:

$F=1.6*10^{-19}C(300\frac{m}{s})(1T)sin(90^\circ)\\F=4.8*10^{-17}N$

3 0

3 years ago

A TV is rated at 0.1 kW. This TV is used 3 hours per day. How much energy does the TV use per month (in kWh)?

exis [7]

Answer:

<em><u>A.9</u></em><em><u> </u></em><em><u>kWh</u></em>

Explanation:

Tv is rated 0.1 kW

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in 30 days energy used will be 0.3kwh×30=9kwh

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4 years ago

What might happen to the mass and/or the distance between two objects to increase the gravitational force of attraction?

goldfiish [28.3K]

The gravitational force may grow weaker if separation occurs with the distance.

hope i helped :)

6 0

3 years ago

What is the wavelength of the light entering an interferometer if 402 bright fringes are counted when the movable mirror moves 0

rusak2 [61]

Answer:

The value is $\lambda = 572 *10^{-9} \ m$

Explanation:

From the question we are told that

The number of bright fringes is n = 402

The displacement of the mirror is $\delta l = 0.115 \ mm = 1.15 *10^{-4} \ m$

Generally the number of fringes is mathematically represented as

$n = \frac{2 * \delta l }{\lambda }$

=> $\lambda = \frac{2 * \delta l }{n }$

=> $\lambda = \frac{2 * 1.15*10^{-4} }{402 }$

=> $\lambda = 572 *10^{-9} \ m$

8 0

4 years ago