Vector question,university physics zemanski pls help me

Physics

1 answer:

kykrilka [37]3 years ago

7 0

Forces are by the cable, gravity and normal force by the incline.

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Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open

Basile [38]

The electrostatic energy stored in a capacitor with capacitance $C_0$ , with a voltage difference V applied to it, and without dielectric, is given by
$U_0 = \frac{1}{2} C_0 V^2$
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
$C_k = k C_0$
So, the energy stored now is
$U_k = \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2$

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
$\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}= k$

5 0

3 years ago

A radioactive substance decays exponentially. A scientist begins with 200 milligrams of a radioactive substance. After 17 hours,

lianna [129]

75.17 mg of the radioactive substance will remain after 24 hours.

Answer:

Explanation:

Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.

Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.

Then Disintegration constant = 0.6932/Half Life time

Disintegration constant = 0.6932/17=0.041

Then as per the law of disintegration constant:

$N = N_{0}e^{-xt}$