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Andrew [12]
3 years ago
7

Vector question,university physics zemanski pls help me

Physics
1 answer:
kykrilka [37]3 years ago
7 0

Forces are by the cable, gravity and normal force by the incline.

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How can acceleration be changed without changing speed?
katrin [286]
Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both. If you're not changing your speed and you're not changing your direction, then you simply cannot be accelerating—no matter how fast you're going.
3 0
2 years ago
Pls help me ill give brainliest
abruzzese [7]

Answer:

c

Explanation:

a, b, and d are examples of moving forward

while c is moving backwards.

4 0
3 years ago
Read 2 more answers
If the net force acting on a moving object CAUSES NO CHANGE IN ITS VELOCITY, what happens to the object's momentum?
SOVA2 [1]

If the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.

<h3>What is momentum?</h3>

Momentum of a body in motion refers to the tendency of a body to maintain its inertial motion.

The momentum is the product of its mass and velocity.

This suggests that if the net force acting on a moving object causes no change in its velocity, the momentum of the object will remain the same.

Therefore, if the net force acting on a moving object causes no change in its velocity, the object's momentum will stay the same.

Learn more about momentum at: brainly.com/question/13554527

#SPJ1

5 0
1 year ago
Why do we tend to attribute others' negative behaviors to dispositions over situational factors?
miskamm [114]

Answer:

Because you have a greater understanding of the mentality and conduct of individuals you care about, you are better able to understand their perspective and are more likely to recognize possible situational factors for their behavior.

4 0
2 years ago
A 6cm diameter horizontal pipe gradually narrows to 4cm.
Rom4ik [11]

Answer:Q=0.5612 m^3/s

Explanation:

Given

diameter of pipe(d_1)=6 cm

diameter of pipe(d_2)=4 cm

P_1=32 kPa

P_2=24 kPa

A_1=\frac{\pi }{4}6^2=9\pi cm^2

A_2=\frac{\pi }{4}4^2=4\pi cm^2

v_1=\frac{Q}{A_1}

Applying bernoulli's equation

\frac{P_1}{\rho g}+\frac{v^2_1}{2g}+z_1=\frac{P_2}{\rho g}+\frac{v^2_2}{2g}+z_2

\frac{P_1}{\rho g}+\frac{\frac{Q^2}{A_1^2}}{2g}+z_1=\frac{P_2}{\rho g}+\frac{\frac{Q^2}{A_2^2}}{2g}+z_2

since z_1=z_2

\frac{32\times 10^3}{10^3\times 9.81}+\frac{Q^2}{2A_1^2g}=\frac{24\times 10^3}{10^3\times 9.81}+\frac{Q^2}{2A_2^2g}

Q^2=\frac{8\times 2\times 81\pi ^2\times 16\pi ^2\times 10^{-4}}{65\pi ^2}

Q^2=3149.3722\times 10^{-4}

Q=\sqrt{3149.3722\times 10^{-4}}

Q=0.5612 m^3/s

4 0
2 years ago
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