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2 years ago

Energy Calculations

Physics

1 answer:

MaRussiya [10]2 years ago

6 0

Answer: 20,734.69 N/m

Explanation:

The elastic potential energy (ELPE) of the rubber band is given by

$E=\frac{1}{2}kx^2$

where

k is the spring constant

x = 0.035 m is the stretching of the rubber band

E = 12.7 J is the ELPE of the rubber band

Substituting the numbers and re-arranging the equation, we find

$k=\frac{2E}{x^2}=\frac{2\cdot 12.7 J}{(0.035 m)^2}=20,734.69 N/m$

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1 year ago

A. If you set a cannonball to 1500 m/s, what happens? Explain why you think it moves this way.

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2 years ago

What is 64 nanometers to m?

defon

$\sf Hello!$

$\sf We\: know \:that,$
$\sf 1\: meter$ = $\sf 10^{9} nm$

$\sf Then,$

$\sf Distance\: in \:m$ = $\sf Distance\: in\: nm$ × $\dfrac{\sf 1}{\sf 10^{9}}\: \sf m$

⇒ $\sf Distance\: in \:m$ = $\sf 64 × 10^{-9} \:m$

⇒ $\sf Distance\: in\: m$ = $\sf 6.4 × 10^{-8} \:m$

~ $\sf iCarl$

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