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Anna35 [415]
3 years ago
5

Pls help me ill give brainliest

Physics
2 answers:
abruzzese [7]3 years ago
4 0

Answer:

c

Explanation:

a, b, and d are examples of moving forward

while c is moving backwards.

Kazeer [188]3 years ago
4 0
I’m pretty sure that your answer is C
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An electron moves along the z-axis with vz=4.1Ã107m/s. As it passes the origin, what are the strength and direction of the magne
Artist 52 [7]

Answer:

a

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive x - axis

b

The value of magnetic field is B_a=6.56*10^{-19} T

In the direction of the positive z - axis

Explanation:

From the question we are told that

         The velocity of the electron is v_z = 4.1*10^{7}m/s

Considering the first position

    The equation for the magnetic field is

                    \= B = \frac{\mu_0}{ 4 \pi} \frac{q \=v * \= r}{r^2}

 Now r = \sqrt{i^2 + j^2 + k^2}

  substituting values

           r = \sqrt{1^2 +0^2 +0^2}

              = 1

          \= r = \frac{\r r}{r}

        \r r = 1 i + 0j + 0k

Therefore \= r = \frac{1i + 0j + 0k}{1}

                   = i

So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * i}{1^2}

                 \= B_a=6.56*10^{-19} T (i)

Considering the second  position

    Here

               r = \sqrt{0^2 + 0^2 + 2^2}

                  =2

              \= r = \frac{\r r}{r}

              \r r = 0 i + 0j + 2k

            \= r = \frac{0i + 0j + 2k}{2}

               = k

 So   Substituting  4 \pi *10^ {-7} for \mu_o , 1.602 *10^{-19} for q

            \= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * k}{1^2}

                 \= B_a=6.56*10^{-19} T (k)

6 0
4 years ago
Where have mars meteorites been founded
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4 years ago
An object at rest requires a force of 15 Newtons to set it into motion
goldfiish [28.3K]

Answer:

The force that required an object to move is greater than friction force. The opposite force for an object in motion is the friction force (assuming that the surface where the object lies is rough as most real objects are). This force is needed to be overcome to set the object to motion.

Explanation:

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3 years ago
A ball is kicked off of a roof at 23 m/s [R 25° U]. What is the height of
Ymorist [56]

Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

v_{0y}=v_0sin\theta and filling in:

v_{0y}=23sin(25) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

v_{0y}=9.7m/s

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = v_0t+\frac{1}{2}at^2 and filling in:

Δx = 9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2 I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + \frac{1}{2}(-9.8)(2.8)^2 and then to the right of the + sign and to 2 significant digits we have

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6 0
3 years ago
The amplitude of the wave in the picture below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm
antiseptic1488 [7]

Answer:

1cm

Explanation:

The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.

8 0
2 years ago
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