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Anna35 [415]
3 years ago
5

Pls help me ill give brainliest

Physics
2 answers:
abruzzese [7]3 years ago
4 0

Answer:

c

Explanation:

a, b, and d are examples of moving forward

while c is moving backwards.

Kazeer [188]3 years ago
4 0
I’m pretty sure that your answer is C
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Before 1960, people believed that the maximum attainable coefficient of static friction for an automobile tire on a roadway was
True [87]

This problem is looking for the minimum value of μs that is necessary to achieve the record time. To solve this problem:


Assuming the front wheels are off the ground for the entire ¼ mile = 402.3 m, the acceleration a = µs·9.8 m/s².


For a constant acceleration, distance = 402.3


m = 1/2at^2 = 804.6 m / (4.43 s)^2 = a = µs·9.8 m/s^2



µs = 804.6 m / (4.43s)^2 / 9.8 m/s^2 = 4.18

5 0
3 years ago
Two obiect accumulated a charge of
tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

q_2=2.8\mu C=2.8\cdot 10^{-6}C is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N

So, the closest answer is

A) 181.24 N

3 0
4 years ago
If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

\\\frac{1}{2}mv^{2} = eV\\\\\frac{1}{2}(9.1\ x\ 10^{-31}\ kg)v^{2} = (1.6\ x\ 10^{-19}\ C)(9900\ volts)\\\\v = \sqrt{34.81\ x\ 10^{14}} \\

<u>v = 5.9 x 10⁷ m/s</u>

8 0
3 years ago
An action potential arriving at the presynaptic terminal causes what to occur?
Ulleksa [173]

Answer:

Voltage-gated calcium ion channels open, and calcium ions diffuse into the cell

5 0
3 years ago
In a galvanic cell, electrons flow from the ________ to the _______ .
s2008m [1.1K]

Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

7 0
3 years ago
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