What a three of the signs of an allergic reaction to iv t-pa?
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Answer:
45.4 L
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 27.9 L
V₂ = ?
P₁ = 732 mmHg
P₂ = 385 mmHg
T₁ = 30.1 ºC
T₂ = -13.6 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (30.1 + 273.15) K = 303.25 K
T₂ = (-13.6 + 273.15) K = 259.55 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 45.4 L</u>
The empirical formula of the hydrocarbon is if combustion of 8.60 g of a hydrocarbon produced 26.5 g of
and 12.2 g of
.
A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule is the empirical formula for glucose.
1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.
Hence, in this case the mass of carbon in 8.46 g of :
() × 8.46 = 2.3073 g
1 mole of water contains 18 g, out of which 2 g is hydrogen;
Therefore, 2.6 g of water contains;
( × 2.6 = 0.2889 g of hydrogen.
Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.
We first calculate the number of moles of each,
Carbon = = 0.1923 moles
Hydrogen = = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;
Carbon : Hydrogen
:
1 : 1.5
(1 : 1.5) 2
= 2 : 3
Hence, the empirical formula of the hydrocarbon is .
Learn more about the empirical formula here:
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