All categories

3 years ago

What happens to an electric current produced from an electromagnet when the direction of the magnetic field changes?

Physics

2 answers:

aev [14]3 years ago

8 0

Answer;

C. The direction of the electric current changes.

Explanation;

An electromagnet is a magnet that runs on electricity. Unlike a permanent magnet, the strength of an electromagnet can easily be changed by changing the amount of electric current that flows through it. The poles of an electromagnet can even be reversed by reversing the flow of electricity.

An electromagnet works because an electric current produces a magnetic field. The magnetic field produced by an electric current forms circles around the electric current

GrogVix [38]3 years ago

7 0

An electromagnet is and electric magnetic field present to a coil of copper around it that attracts metal and other electricity. Based in your question about the changing of the direction of the current, I think the amount of electromagnetic field doesnt change but the polarity does.

You might be interested in

According to the law of conservation of energy, which statement must be

alina1380 [7]

Answer: THE ANSWER IS C!

The total energy of a system can decrease only if energy leaves the system.

Explanation: Apex!

7 0

3 years ago

Which of these is an example of convection?

uranmaximum [27]

Which of these is an example of convection?

<u> A. an egg boiling in water </u>

B. an egg frying in a pan

C. an egg exposed to a flame

D. an egg warming under a light

5 0

3 years ago

Read 2 more answers

Radiometric dating is done by comparing the ratio of _____. A. two radioactive isotopes over time. B. a stable isotope to a deca

konstantin123 [22]

The answer should be B. a stable isotope to a decaying isotope.

7 0

3 years ago

Read 2 more answers

Water (density = 1x10^3 kg/m^3) flows at 15.5 m/s through a pipe with radius 0.040 m. The pipe goes up to the second floor of th

RUDIKE [14]

Answer:

The speed of the water flow in the pipe on the second floor is approximately 13.1 meters per second.

Explanation:

By assuming that fluid is incompressible and there are no heat and work interaction through the line of current corresponding to the pipe, we can calculate the speed of the water floor in the pipe on the second floor by Bernoulli's Principle, whose model is:

$P_{1} + \frac{\rho\cdot v_{1}^{2}}{2}+\rho\cdot g\cdot z_{1} = P_{2} + \frac{\rho\cdot v_{2}^{2}}{2}+\rho\cdot g\cdot z_{2}$ (1)

Where:

$P_{1}$ , $P_{2}$ - Pressures of the water on the first and second floors, measured in pascals.

$\rho$ - Density of water, measured in kilograms per cubic meter.

$v_{1}$ , $v_{2}$ - Speed of the water on the first and second floors, measured in meters per second.

$z_{1}$ , $z_{2}$ - Heights of the water on the first and second floors, measured in meters.

Now we clear the final speed of the water flow:

$\frac{\rho\cdot v_{2}^{2}}{2} = P_{1}-P_{2}+\rho \cdot \left[\frac{v_{1}^{2}}{2}+g\cdot (z_{1}-z_{2}) \right]$

$\rho\cdot v_{2}^{2} = 2\cdot (P_{1}-P_{2})+\rho\cdot [v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})]$

$v_{2}^{2}= \frac{2\cdot (P_{1}-P_{2})}{\rho}+v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})$

$v_{2} = \sqrt{\frac{2\cdot (P_{1}-P_{2})}{\rho}+v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2}) }$ (2)

If we know that $P_{1}-P_{2} = 0\,Pa$ , $\rho=1000\,\frac{kg}{m^{3}}$ , $v_{1} = 15.5\,\frac{m}{s}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $z_{1}-z_{2} = -3.5\,m$ , then the speed of the water flow in the pipe on the second floor is: